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3 years ago

Draw a possible function that satisfy the given domain and range

Mathematics

1 answer:

NikAS [45]3 years ago

5 0

9514 1404 393

Answer:

see attached.

Step-by-step explanation:

Your graph demonstrates a possible function, but it has the domain and range swapped.

The domain is the horizontal extent, so your line must end at x=-9 on the left and x=6 on the right.

The range is the vertical extent, so the function must extend from -4 at the bottom to +8 at the top.

The attachment shows a linear function with those characteristics.

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Use the given conditions to write an equation for each line in general form.

Aneli [31]

Answer:

It's the last choice:

2x + y - 1 = 0.

Step-by-step explanation:

x - 2y - 3 = 0

Convert to slope-intercept form in order to find the slope:

-2y = -x + 3

y = 1/2x - 3/2

So the slope is 1/2. The slope of a line perpendicular to this is -1 / 1/2 = -2.

Using the point-slope form to find the required equation:

y - y1 = m(x - x1)

x = 4 and y = -7 so we have:

y + 7 = -2(x - 4)

y + 7 = -2x + 8

2x + y - 1 = 0 is the answer.

6 0

3 years ago

Elmer sees a flying saucer. The radius of the flying saucer is 17 feet. What is the area of the flying saucer (use 3.14 for pi a

sergiy2304 [10]

Answer:

Area of the flying saucer = $907.46 ft^2$

Step-by-step explanation:

The Flying saucer is in the shape of a circle.

$Radius= 17 feet$

Area of the circular flying saucer= $\pi *r*r$

: $\pi =\frac{22}{7} =3.14$

Area= $3.14*17*17$

Area of the flying saucer $=3.14*289\\\\ =907.46 ft^2$

So, the area of the flying saucer is $907.46 ft^2$

8 0

3 years ago

A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the

amm1812

Answer:

$s(t)=(ln|7|+ln|2|)\,ft$

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

$a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\$

Integrating both sides w.r.to t

$v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\$

Using initial value

$v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}$

We have to calculate the distance covered in time interval [0,5], so:

$\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft$

3 0

3 years ago

What are the first 50 digits of pi

avanturin [10]

Answer: 3.14159265358979323846264338327950288419716939937510

i believe it is.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Plz help me with this

Salsk061 [2.6K]

Answer: $\bold{b)\quad \dfrac{x+3}{4}}$

Step-by-step explanation:

$y=4x-3\\\\\text{Swap the x's and y's. Then solve for y:}\\x=4y-3\\\\\text{Add 3 to both sides:}\\x+3=4y\\\\\text{Divide both sides by 4:}\\\large\boxed{\dfrac{x+3}{4}=y}$

4 0

3 years ago

Draw a possible function that satisfy the given domain and range​

Draw a possible function that satisfy the given domain and range