1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dima020 [189]
3 years ago
11

laws of Sines all together. Find each measurement indicated. Round your answers to the nearest tenth. Part 1 Please show your wo

rk.​

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:

1. 23.0 cm

2. 21.0 ft

3. 31.0 yd

Step-by-step explanation:

erik [133]3 years ago
3 0

Answer:

1. 23.0 cm

2. 21.0 ft

3. 31.0 yd

Step-by-step explanation:

1. 30/sin110 = RT/sin46

RT = sin46 × 30/sin110

RT = 22.96516279

2. Angle A = 180 - 61 - 53 = 66°

24/sin66 = AB/sin53

AB = sin53 × 24/sin66

AB = 20.98116966

3. 18/sin28 = HP/sin54

HP = sin54 × 18/sin28

HP = 31.01850475

You might be interested in
Simplify. Brainliest, help asap! <3
Mariana [72]
-4 for the first one and 2/3 for the second
8 0
3 years ago
Read 2 more answers
Plz help quickly!!!! You will get 36 POINTS!!!
liq [111]
If clearer picture i may help for it is far to dark and clouded to read

4 0
3 years ago
Read 2 more answers
Determine which equation is parallel to the line JK and which is perpendicular to like JK
sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and y = - \frac{1}{m}x + b will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as  

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be  

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation  

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ n = - \frac{1}{m}

Therefore, the equation of a straight line which is perpendicular to equation (1) will be y = - \frac{1}{m}x + b where b is any real constant. (Answer)

3 0
3 years ago
Read 2 more answers
Which property of real numbers is shown below? 3 + ((-5) + 6) = (3 + (-5)) + 6 commutative property of addition identity propert
Sati [7]

Answer:

The correct answer is the associative property of addition.

Step-by-step explanation:

This property states that no matter which way we group things when adding, they will still create the same outcome. Since all of the symbols are addition, the answer is the same.

5 0
3 years ago
Read 2 more answers
The annual snowfall in a town has a mean of 38 inches and a standard deviation of 10 inches. Last year there were 63 inches of s
padilas [110]
This is 2.5 standard deviations from the mean.

We find this by subtracting the mean from our value, and dividing by the standard deviation:
(63-38)/10 = 25/10 = 2.5
8 0
3 years ago
Other questions:
  • Could someone help me on 6 7 and 8? So confused!!!!
    11·1 answer
  • Round 2.408 to the nearest hundredth
    14·2 answers
  • You have 7/8 cups of sour cream to make tacos . If each taco requires 1/16 cup of sour cream how many tacos can you make
    14·2 answers
  • Is the slope of the linear positive, negative,zero, or undefined<br> y=-x+5
    6·1 answer
  • the water temperature of a swimming pool is 76f. the temperature is currently 74f. which graph shows how much the temperature ne
    6·1 answer
  • I really need help with this question
    13·1 answer
  • Chu kỳ của hàm số y=sin 4 là:
    15·1 answer
  • I need help picture below
    14·1 answer
  • Please help! I am confused.
    8·1 answer
  • Describe van Hiele Level 1 (analysis), Level 2 (informal deduction) and Level 3 (deduction). Demonstrate the difference by using
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!