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2 years ago

(06.02 LC) Which of the following algebraic expressions can be used to express the statement "five less than y squared?"

Mathematics

1 answer:

mixas84 [53]2 years ago

7 0

Answer:

Step-by-step explanation:

it is saying to subtract five from y^2

y^2-5

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3 years ago

A newly established clothing shop analyzed their monthly profit compared to the amount spent on advertising each month. The foll

Reil [10]

The maximum profit is the highest point on the curve at (3, 45), and since the y-value is the profit in hundreds of dollars, the maximum profit is $4500.
The shop is making a profit as long as the curve is above the x-axis, so this is over the given interval (0, 10).
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2 years ago

Read 2 more answers

Neeeeed helpppppp please

MissTica

Answer:

Scale factor = 7

Step-by-step explanation:

Dilation with scale factor to map HEFG to DABC will be,

Scale factor = $\frac{\text{Dimension of Image DABC}}{\text{Dimension of preimage HEFG}}$

= $\frac{\text{Length of CD}}{\text{Length of GH}}$

Length of CD = Distance between two points C(0, -7) and D(-7, 0)

= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

= $\sqrt{(-7-0)^2+(0+7)^2}$

= $\sqrt{98}$

= $7\sqrt{2}$

Length of GH = Distance between G(0, -1) and H(-1, 0)

= $\sqrt{(-1-0)^2+(0+1)^2}$

= $\sqrt{2}$

Scale factor = $\frac{7\sqrt{2} }{\sqrt{2} }$

= 7

6 0

3 years ago

Question 12 Multiple Choice Worth 1 points)(07.05 MC)1086Which of the following functions best represents the graph?fix)=(x-2)(x

vlada-n [284]

The graph of a function is given. It is required to find the function that represents the graph.

Notice from the graph that the function has roots or zeros at -3,-2, and 2.

Hence, the function takes the form:

$\begin{gathered} f(x)=a(x-(-3))(x-(-2))(x-2) \\ \Rightarrow f(x)=a(x+3)(x+2)(x-2) \end{gathered}$

Where a is a constant to be determined.

Notice that the given graph passes through the point (0,-12).

Substitute x=0 and f(x)=-12 into the equation of the function to find a:

$\begin{gathered} -12=a(0+3)(0+2)(0-2) \\ \Rightarrow-12=a(3)(2)(-2) \\ \Rightarrow-12=-12a \\ \text{ Swap the sides of the equation:} \\ \Rightarrow-12a=-12 \\ \text{ Divide both sides by }-12: \\ \Rightarrow\frac{-12a}{-12}=\frac{-12}{-12} \\ \Rightarrow a=1 \end{gathered}$

Hence, the function is:

$\begin{gathered} f(x)=1(x+3)(x+2)(x-2) \\ \Rightarrow f(x)=(x+2)(x+3)(x-2) \end{gathered}$ <h2>The third option is the answer: f(x)=(x+2)(x+3)(x-2).</h2>

5 0

1 year ago