Answer:
2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)
Explanation:
First, write the half equations for the reduction of MnO4^- and the oxidation of C2O4^2- respectively. Balance it.
Reduction requires H+ ions and e- and gives out water, vice versa for oxidation.
Reduction:
MnO4^- (aq) + 4H^+ (aq) + 3e- ---> MnO2(s) + 2H2O (l)
Oxidation:
C2O4^2- (aq) + 2H2O (l) ---> 2CO3^2 -(aq) + 4H^+ (aq) + 2e-
Balance the no. of electrons on both equations so that electrons can be eliminated. we can do so by multiplying the reduction eq by 2, and oxidation eq by 3.
2MnO4^- (aq) + 8H^+ (aq) + 6e- ---> 2MnO2(s) + 4H2O (l)
3C2O4^2- (aq) + 6H2O (l) ---> 6CO3^2 -(aq) + 12H^+ (aq) + 6e-
Now combine both equations and eliminate repeating H+ and H2O.
2MnO4^- (aq) + 8H^+ (aq) + 3C2O4^2- (aq) + 6H2O (l) --> 2MnO2(s) + 4H2O (l) +6CO3^2 -(aq) + 12H^+ (aq)
turns into:
2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)
one substance becomes two new substances
Energy may only be transformed from one sort to another. hope this helps :)
Answer:
10 km/hr
Explanation:
We are told that a jogger runs;
3km in 0.3 hr and
7 km in 0.7 hr
We are required to determine the average speed;
We need to know that average speed is given by;
Average speed = Total distance ÷ total time
In this case;
Total distance = 10 km ( 3km + 7 km)
Total time = 0.3 hr + 0.7 hr
= 1 hr
Thus;
Average speed = 10 km ÷ 1 hr
= 10 km/hr
Therefore, the average speed of the jogger is 10 km/hr
Answer:
Recibir y analizar la información y producir respuestas.
Explicación:
Las principales funciones del sistema nervioso es recibir información del entorno externo y produce respuestas a la información recibida. El sistema nervioso comprende el cerebro y la médula espinal que controla todo el cuerpo. hay células sensoriales presentes en la piel que reciben estímulos externos y a través de las neuronas la información se transfiere al sistema nervioso. después de procesar la información, la respuesta se envía a los músculos para que actúen frente a los estímulos externos.
