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4 years ago

How would you experiment to find out how much water this plant type needs for optimal growth

Chemistry

2 answers:

Vlad1618 [11]4 years ago

8 0

Answer:

The correct answer will be- by providing different amount of water to experimental groups.

Explanation:

The scientific experimental samples are divided into two groups: the control group in which the variable to be studied is kept constant and the experimental variable to which different amount of studied variable is provided.

In the given question, the scientific question is how much amount of water is required for the optimal growth of the plants. The variable to be studied is water, so different amount of water is provided to different pots like 10 ml, 20 ml, 30 ml and so on. So the plant which will respond best to this amount will be the optimal concentration of the water required by the plant to grow.

PilotLPTM [1.2K]4 years ago

6 0

You would pick amounts of water as your IV and do like 0 mL, 20 mL, 40 mL, and 60 mL as groups (for example, amount can be changed). Whichever had the best growth in the certain amount of time, with all other variables constant, would be it.

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A gas has a volume of 62.65 L at STP. At what temperature (in oC) would the volume of the gas be 78.31 L at a pressure of 612.0

masha68 [24]

Answer:

1.788 C DEGREES

Explanation:

STP is 1 atm at 273.15 K

P1V1/T1 = P2V2/T2

(1)(62.65) / (273.15) = (612/760)(78.31)/T2

T2 = 274.93 K = 1.788 C

5 0

2 years ago

Which of the following structures surround cells?

8090 [49]

Cells are surrounded by #2 , Cell membrane and Cell wall thats what protects the cell

4 0

3 years ago

Arrange the following units in decreasing order: nm,km,pm,Dm,mm,m,cm,hm,gm

goblinko [34]

The units are nm (nano-meter), km (kilo-meter), pm (pico-meter), dm (decimeter), mm (millimeter), m (meter), cm (centimeter), hm (hectometer) and gm (gigameter). Now we can express each of these units in terms of m.

1 nm = $10^{-9}m$ , 1 Km = $10^{3}m$ 1 pm = $10^{-12}m$ , 1 dm = 0.1 m, 1 mm = 0.001 m, 1 cm = 0.01 m, 1 hm = 100 m, 1 gm = $10^{9} m$ . Thus the decreasing unit will be

gm>km>hm>m>dm>cm>mm>nm>pm

3 0

3 years ago

When there are 0.0814 moles of hockey pucks how many hockey pucks are there?

Dovator [93]

Answer:

4.9 x 10²²hockey pucks

Explanation:

Given parameters:

Number of moles of hockey = 0.0814moles

Unknown:

Number of pucks there = ?

Solution:

A mole of a substance is made up of Avogadro's number of particles.

Therefore;

1 mole of hockey pucks will contain 6.02 x 10²³ hockey pucks

0.0814 mole of hockey pucks will contain :

0.0814 x 6.02 x 10²³ = 4.9 x 10²²hockey pucks

8 0

3 years ago

If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?

Darina [25.2K]

The question is incomplete, here is the complete question:

A bottle of rubbing alcohol having aqueous solution of alcohol contains 70% (v/v) alcohol. If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?

<u>Answer:</u> The amount of water present in the given bottle of rubbing alcohol is 283.8 mL

<u>Explanation:</u>

We are given:

Volume of bottle of rubbing alcohol = 946 mL

70% (v/v) alcohol solution

This means that 70 mL of rubbing alcohol is present in 100 mL of solution

Amount of water present in solution = [100 - 70] = 30 mL

Applying unitary method:

In 100 mL of solution, the amount of water present is 30 mL

So, in 946 mL of solution, the amount of water present will be = $\frac{30}{100}\times 946=283.8mL$

Hence, the amount of water present in the given bottle of rubbing alcohol is 283.8 mL

4 0

3 years ago