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charle [14.2K]
3 years ago
9

*Fill in the blanks with the correct letters* (You don't have to explain it I just need the answers please)

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
<span>7x^2 + 7y^2 - 28x + 42y - 35 = 0.
⇒ </span><span>x^2 + y^2 - 4x + 6y - 5 = 0.
⇒ (x-2)^2 + (y+3)^2 = 18

1. B
2. C
3. B
</span>
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State the correct answers.​
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(part B) C≈4m

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Solve the equation:<br> [3 2<br> 5 5]<br><br> [x1<br> x2]+<br> [1<br> 2]=<br> [2<br> -3]
dsp73

9514 1404 393

Answer:

  (x1, x2) = (3, -4)

Step-by-step explanation:

As with any 2-step linear equation, subtract the constant, then multiply by the inverse of the coefficient of the variable.

  \left[\begin{array}{cc}3&2\\5&5\end{array}\right]\left[\begin{array}{c}x\\y\end{array}\right]+\left[\begin{array}{c}1\\2\end{array}\right]=\left[\begin{array}{c}2\\-3\end{array}\right]\\\\\left[\begin{array}{cc}3&2\\5&5\end{array}\right]\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}1\\-5\end{array}\right]\\\\\left[\begin{array}{c}x\\y\end{array}\right]=\dfrac{1}{5}\left[\begin{array}{cc}5&-2\\-5&3\end{array}\right]\left[\begin{array}{c}1\\-5\end{array}\right]

Performing the multiplication of the matrix by the vector gives the solution.

  x = ((5)(1) +(-2)(-5))/5 = 15/5 = 3

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Using your variables, x1, x2, the solution is ...

  (x1, x2) = (3, -4)

7 0
2 years ago
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