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MatroZZZ [7]
3 years ago
10

The perimeter of a rectangle is 160 meters. If the length of the rectangle is 30 meters more than the width, what are the dimens

ions of the rectangle?
How on earth do I set this up?

Mathematics
1 answer:
Maslowich3 years ago
3 0
The answer is ; 25 meters is the width
I showed my explanation below

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Please help im struggling so much
Serggg [28]

Answer:

B. y=-10,250

C. 6 payments

Sorry for my terrible handwriting.. Hope this helps tho! Have a great day/night!

8 0
2 years ago
How do I solve these equations
Sever21 [200]
You need to know the properties of each function.
Tan is opposite (y) over adjacent (x).  Sin>0 means that sin is positive, therefore, it is located on either quadrant 1 or 2. Tan=4/3  so it is located in quadrant 1.
The side of the triangle must be Adjacent=3  opposite=4 and hypotenuse=5
Now, you are asked to find the half angle of Cos which is 
\sqrt{\frac{1+cos}{2} }
By following the formula, cos=3/5 then:
\sqrt{ \frac{1- \frac{3}{5} }{2} }    Multiply everything (inside the square          \sqrt{ \frac{5+3}{10} }                  root) by 5
\frac{2 \sqrt{2} }{ \sqrt{10} }
\frac{2 \sqrt{20} }{10}                Then just simplify
\frac{ \sqrt{20} }{5}      The answer is Square root of 20 over 5
3 0
3 years ago
Please help I will make BRAINLIEST!!!!!
Anon25 [30]

Answer:

variable= x

x ≤ 100

Step-by-step explanation:

it would be x ≤ 100 because it says it can hold as many AS 100, making it less than or equal to 100

3 0
3 years ago
Why did I get this question wrong?
lord [1]

Step-by-step explanation:

∫₀³⁰ (r/V C₀ e^(-rt/V)) dt

If u = -rt/V, then du = -r/V dt.

∫ -C₀ e^u du

-C₀ ∫ e^u du

-C₀ e^u + C

-C₀ e^(-rt/V) + C

Evaluate between t=0 and t=30.

-C₀ e^(-30r/V) − -C₀ e^(-0r/V)

-C₀ e^(-30r/V) + C₀

C₀ (-e^(-30r/V) + 1)

I got the same answer.  Try changing the lowercase v to an uppercase V.

4 0
3 years ago
Please help asap pleaseeeew
wel

Answer:

6.

Step-by-step explanation:

1) OA=d/2=20/2=10;

2) AB=AC/2=16/2=8;

3) \ OB=\sqrt{OA^2-AB^2} =6.

3 0
2 years ago
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