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zloy xaker [14]
4 years ago
10

Payton can type 75 words per minute. How manywords can she type in 1 hour and 23 minutes?​

Mathematics
1 answer:
Eddi Din [679]4 years ago
4 0

Answer:

She can type 6,225 words in 1 hour and 23 minutes

Step-by-step explanation:

1 hour = 60 minutes so you convert the hour into minutes and add 60 + 23 to get 83. From here you just multiply 75 (words per minute) and 83 (amount of minutes) and you get 6,225

You might be interested in
Which graph represents a reflection of f(x) = 6(0.5)x across the x-axis?
yawa3891 [41]

Answer:

  • The graph that represents a reflection of f(x) across the x-axis is the blue line on the picture attached.

Explanation:

The function f(x) is:

  • f(x)=6(0.5)^x

Which is an exponential function with these features:

  • y-intercept: f(0) = 6(0.5)⁰ = 6(1) = 6

  • multiplicative rate of change: 0.5 (the base of the exponential term), which means that it is a decaying function (decreasing)

  • Horizontal asympote: y = 0 (this is the limit of f(x) when x approaches +∞.

The reflection of f(x) across the x-axis is a function g(x) such that g(x) = - f(x).

Thus, the reflection of f(x) across the x-axis is:

  • g(x)=-6(0.5)^x

The features of that function are:

  • Limit when x approaches - ∞: -∞ (thus the function starts in the third quadrant).

  • y-intercerpt: g(0) = -6 (0.5)⁰ = -6(1)= - 6.

  • Horizontal asympote: y = 0 (this is the limit of f(x) when x approaches +∞.

  • Note that the function never touches the x-axis, thus the function increases from -∞, crosses the y-axis at (0, -6) and continous growing approaching the x-axis but never touchs it. So, this is an increasing frunction, that starts at the third quadrant and ends in the fourth quadrant.

With those descriptions, you can sketch the graph, which you can see in the figure attached. There you have the function f(x) (the red increasing line) and its reflection across the x-axis (the blue increasing line).

5 0
3 years ago
Read 2 more answers
Please help me my mums gonna kill me if I fail this assignment.
Vika [28.1K]

Answer:

17 in,3 in, and 19in

so the third answer

Step-by-step explanation:

6 0
4 years ago
Hurry please help me!
Dennis_Churaev [7]

Answer:

  • d. 23

Step-by-step explanation:

Let the number of cars be x and buses be y

<u>Then we have below inequalities as per given:</u>

  • 5x + 32y ≤ 1310
  • x + y ≤ 135

It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income

<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>

  • x = 135 - y

<u>Substitute it in the first one:</u>

  • 5(135 - y) + 32y ≤ 1310
  • 675 - 5y + 32y ≤ 1310
  • 27y ≤ 1310 - 675
  • 27y ≤ 635
  • y ≤ 635/27
  • y≤ 23.5

The greatest number of buses is 23

Option D. 23 is correct

5 0
4 years ago
(x-3)(x+4) please send the help
miss Akunina [59]

Answer:

x^2 + x -12

Step-by-step explanation:

I am going to expand and simplify because you haven't mentioned what to do:

(x-3)(x+4)

x^2 +4x -3x- 12

x^2 +x-12

7 0
3 years ago
Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time
user100 [1]

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

x ≥ 0, y ≥ 0

Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours  

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative  

5 0
3 years ago
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