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exis [7]
3 years ago
8

Need help ASAP!!!!!!

Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

x² + 3x + 7 = 5 ( subtract 5 from both sides )

x² + 3x + 2 = 0 ← in standard form

(x + 2)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x ( zero product rule )

x + 2 = 0 → x = - 2

x + 1 = 0 ⇒ x = - 1

--------------------------------------------------------------

x² - 2 = - 2x² + 5x ( subtract - 2x² + 5x from both sides )

3x² - 5x - 2 = 0 ← in standard form

(3x + 1)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

3x + 1 = 0 ⇒ 3x = - 1 ⇒ x = - \frac{1}{3}

x - 2 = 0 ⇒ x = 2

------------------------------------------------------------

(x + 3)² + 4x = 0 ← expand left side using FOIL and simplify

x² + 6x + 9 + 4x = 0

x² + 10x + 9 = 0 ← in standard form

(x + 9)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x + 1 = 0 ⇒ x = - 1

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a hexagon inscribed in a circle has three consecutive sides each of length 3 and three consecutive sides each of length 5. the c
allochka39001 [22]

According to given conditions, m+n is equal to 409.

Consider the diagram below.

In the hexagon ABCDEF, let

AB = BC = CD = 3;

DE = EF = FA = 5;

Arc BAF is equal to one-third of the circle's circumference.

Hence, ∠BCF = ∠BEF = 60°;

Similarly, ∠CBE = ∠CFE = 60°;

Let the point of intersection of BE and CF be P, BE and AD be Q and CF and AD be R.

∴ Δ EFP and Δ BCP are equilateral, and so Δ PQR is also equilateral.

Also, ∠ BAD and ∠ BED subtend the same arc and so do ∠ ABE and ∠ ADE.

∴ Δ ABQ is similar to Δ EDQ

\frac{AQ}{EQ}  = \frac{BQ}{DQ} = \frac{AB}{ED} = \frac{3}{5}

Also,

\frac{\frac{AD - PQ}{2} }{PQ + 5} = \frac{3}{5}  

and \frac{3 - PQ}{\frac{AD + PQ}{2} }  = \frac{3}{5}

On solving these simultaneous equations, we get AD = 360/49

∴ m + n = 409.

To learn more about similarity of triangles, refer to this link:

brainly.com/question/25882965

#SPJ4

4 0
1 year ago
What is the equation of the given line in the point-slope form
Genrish500 [490]
First using the given two points we can find the slope (m) of the line

Slope = m =  \frac{Rise}{Run} \\  \\ 
m= \frac{4-1}{3-0} \\  \\ 
m=1

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Using slope and a point (0,1) we can write the equation in point slope form as

y - 1= 1(x-0)
y - 1 = x

The above equation is the point-slope form of the equation.
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3 years ago
Could somebody solve this
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Rewrite by completing the square 2x^2+7x+6=0
Kitty [74]

Answer:

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Which choice is the solution to the inequality below?<br> 2 x &lt; 20
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