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NISA [10]
3 years ago
13

Kate have 110 bows. 10 bows fit in a bag. how many bags can she fill

Mathematics
1 answer:
posledela3 years ago
8 0
11 bags can be filled with bows
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An item is on sale for $12.00. It originally was $16.50.
lbvjy [14]

Answer:

C

Step-by-step explanation:

Decreased price = 16.50 - 12 = $ 4.50

Percent of decrease =

=\frac{4.50}{16.50}*100\\\\= 27.27

= 27%

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What is the correct answer? please only put the answer.
KatRina [158]

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156

Step-by-step explanation:

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No i got autocorrected i meant guess whos trying not to lose progress in hurting me
cupoosta [38]

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what

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3 years ago
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the equation of the line a is given as y = -3/4 x -2. Suppose the line a is parallel to line b and lime t is perpendicular to li
Burka [1]

Answer: The equation for line b is y = -\frac{3}{4}x  + 5

The equation for line t is y= \frac{4}{3} x+5

The attachment shows the original line in green, the parallel line b in red, and the perpendicular line t in blue.

Step-by-step explanation: Use slope intercept form, y = mx + b

The given coordinate, (0,5) is on the y-axis, so  5 will be the y-intercept of the equation. Keep the slope of the original equation and substitute the new value for "b"  

To write the equation for line t

Both lines share the y-intercept, (0,5) so the "b" term will be the same. The slope of a perpendicular line is the reciprocal of the original slope with the opposite sign.

So invert 3/4 to become 4/3 and change the negative sign to positive.

The resulting equation is y = 4x/3 + 5

3 0
3 years ago
3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

8 0
3 years ago
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