Which object has the most thermal energy?

How much work was done to accelerate a 2.2 kg object from rest to 26m/s?

Makovka662 [10]

Answer:

Explanation:

work done = change in kinetic energy, assuming there are no energy losses.

work done = 1/2 × m × change in v^2

= 1/2 × 2.2 × ( 26^2 - 0^2)

= 1/2 × 2.2 × 676

= 743.6 joules

4 0

2 years ago

Which statement best defines work?

DochEvi [55]

Answer:

c

Explanation:

I would think it would be c because that is what I would chose

3 0

3 years ago

Could an elephant have the same momentum as a golf ball

aleksandr82 [10.1K]

Answer:

Since momentum equals mass times velocity, a very slow-moving elephant could have the same momentum as a very fast-moving golf ball. ... m/s because momentum is conserved.

8 0

3 years ago

Read 2 more answers

Heat is allowed to flow from the heat source of a heat engine at 425 K to a cold sink at 313 K. What is the efficiency of the he

olga2289 [7]

I assume here that the engine operates following a Carnot cycle, which achieves the maximum possible efficiency.

Under this assumption, the efficiency of the engine (so, the efficiency of the Carnot cycle) is given by
$\eta = 1- \frac{T_{cold}}{T_{hot}}$
where
$T_{cold}$ is the cold temperature
$T_{hot}$ is the hot temperature

For the engine in our problem, the cold temperature is 313 K while the hot temperature is 425 K, so the effiency of the engine is
$\eta=1- \frac{313 K}{425 K}=0.264 = 26.4 \%$

3 0

4 years ago

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A particle (m = 3.8 × 10-28 kg) starting from rest, experiences an acceleration of 2.4 × 107 m/s2 for 5.0 s. What is its de Brog

Mazyrski [523]

Answer: The De broglie's wavelength is 1.45×10^-14m

Explanation:

Using De broglie's equation

λ= h/mv

Where h= Planck's constant = 6.6×10^-34Js

m= mass in kilogram = 3.8×10^-28kg

V= velocity = acceleration ×time =

2.4×10^7 ×5

V= 1.2×10^8m/s

λ= is the De broglie's wavelength

λ= 6.6×10^-34Js /(3.8×10^-28kg ×1.2×10^8)

λ= 1.45×10^-14m

Therefore ,De broglie's wavelength=

1.45×10^-14m

4 0

4 years ago