Explanation:
Assume that mass of Earth is M, radius of earth orbit is R, and rotational period of Earth is T.
The angular momentum of Earth is,
![L_{z} &=M R^{2} \omega \\ &=M R^{2}\left(\frac{2 \pi}{T}\right) \\ &=\frac{2 \pi M R^{2}}{T}](https://tex.z-dn.net/?f=L_%7Bz%7D%20%26%3DM%20R%5E%7B2%7D%20%5Comega%20%5C%5C%0A%26%3DM%20R%5E%7B2%7D%5Cleft%28%5Cfrac%7B2%20%5Cpi%7D%7BT%7D%5Cright%29%20%5C%5C%0A%26%3D%5Cfrac%7B2%20%5Cpi%20M%20R%5E%7B2%7D%7D%7BT%7D)
The mass of mars is, mass of Earth
=0.11 M
The radius of mars orbit is, of radius of earth
=0.53 R
The rotational period of mars is, of period of Earth
=1.03 T
The angular momentum of mars is,
![L_{m}=\frac{2 \pi(0.11 M)(0.53 R)^{2}}{1.03 T}](https://tex.z-dn.net/?f=L_%7Bm%7D%3D%5Cfrac%7B2%20%5Cpi%280.11%20M%29%280.53%20R%29%5E%7B2%7D%7D%7B1.03%20T%7D)
The angular momentum of mars is,
![L_{m}=\frac{2 \pi(0.11 M)(0.53 R)^{2}}{1.03 T}](https://tex.z-dn.net/?f=L_%7Bm%7D%3D%5Cfrac%7B2%20%5Cpi%280.11%20M%29%280.53%20R%29%5E%7B2%7D%7D%7B1.03%20T%7D)
The ratio of angular momentum of mars to that of earth is,
![\frac{L_{m}}{L_{E}}=\frac{\frac{2 \pi(0.11 M)(0.53 R)^{2}}{1.03 T}}{\frac{2 \pi M R^{2}}{T}} \\ \frac{L_{m}}{L_{E}}=0.03 \\ \frac{L_{m}}{L_{B}}=3.0 \times 10^{-2}](https://tex.z-dn.net/?f=%5Cfrac%7BL_%7Bm%7D%7D%7BL_%7BE%7D%7D%3D%5Cfrac%7B%5Cfrac%7B2%20%5Cpi%280.11%20M%29%280.53%20R%29%5E%7B2%7D%7D%7B1.03%20T%7D%7D%7B%5Cfrac%7B2%20%5Cpi%20M%20R%5E%7B2%7D%7D%7BT%7D%7D%20%5C%5C%0A%5Cfrac%7BL_%7Bm%7D%7D%7BL_%7BE%7D%7D%3D0.03%20%5C%5C%0A%5Cfrac%7BL_%7Bm%7D%7D%7BL_%7BB%7D%7D%3D3.0%20%5Ctimes%2010%5E%7B-2%7D)