Answer:
Part 1) Australia ![19,751,012\ people](https://tex.z-dn.net/?f=19%2C751%2C012%5C%20people)
Part 2) China ![1,319,645,764\ people](https://tex.z-dn.net/?f=1%2C319%2C645%2C764%5C%20people)
Part 3) Mexico ![109,712,539\ people](https://tex.z-dn.net/?f=109%2C712%2C539%5C%20people)
Part 4) Zaire ![60,534,681\ people](https://tex.z-dn.net/?f=60%2C534%2C681%5C%20people)
Step-by-step explanation:
we know that
The equation of a exponential growth function is given by
![P(t)=a(1+r)^t](https://tex.z-dn.net/?f=P%28t%29%3Da%281%2Br%29%5Et)
where
P(t) is the population
t is the number of years since year 2000
a is he initial value
r is the rate of change
Part 1) Australia
we have
![a=19,169,000\\r=0.6\%=0.6\100=0.006](https://tex.z-dn.net/?f=a%3D19%2C169%2C000%5C%5Cr%3D0.6%5C%25%3D0.6%5C100%3D0.006)
substitute
![P(t)=19,169,000(1+0.006)^t](https://tex.z-dn.net/?f=P%28t%29%3D19%2C169%2C000%281%2B0.006%29%5Et)
![P(t)=19,169,000(1.006)^t](https://tex.z-dn.net/?f=P%28t%29%3D19%2C169%2C000%281.006%29%5Et)
Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation
![P(5)=19,169,000(1.006)^5=19,751,012\ people](https://tex.z-dn.net/?f=P%285%29%3D19%2C169%2C000%281.006%29%5E5%3D19%2C751%2C012%5C%20people)
Part 2) China
we have
![a=1,261,832,000\\r=0.9\%=0.9\100=0.009](https://tex.z-dn.net/?f=a%3D1%2C261%2C832%2C000%5C%5Cr%3D0.9%5C%25%3D0.9%5C100%3D0.009)
substitute
![P(t)=1,261,832,000(1+0.009)^t](https://tex.z-dn.net/?f=P%28t%29%3D1%2C261%2C832%2C000%281%2B0.009%29%5Et)
![P(t)=1,261,832,000(1.009)^t](https://tex.z-dn.net/?f=P%28t%29%3D1%2C261%2C832%2C000%281.009%29%5Et)
Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation
![P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people](https://tex.z-dn.net/?f=P%285%29%3D1%2C261%2C832%2C000%281.009%29%5E5%3D1%2C319%2C645%2C764%5C%20people)
Part 3) Mexico
we have
![a=100,350,000\\r=1.8\%=1.8\100=0.018](https://tex.z-dn.net/?f=a%3D100%2C350%2C000%5C%5Cr%3D1.8%5C%25%3D1.8%5C100%3D0.018)
substitute
![P(t)=100,350,000(1+0.018)^t](https://tex.z-dn.net/?f=P%28t%29%3D100%2C350%2C000%281%2B0.018%29%5Et)
![P(t)=100,350,000(1.018)^t](https://tex.z-dn.net/?f=P%28t%29%3D100%2C350%2C000%281.018%29%5Et)
Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation
![P(5)=100,350,000(1.018)^5=109,712,539\ people](https://tex.z-dn.net/?f=P%285%29%3D100%2C350%2C000%281.018%29%5E5%3D109%2C712%2C539%5C%20people)
Part 4) Zaire
we have
![a=51,965,000\\r=3.1\%=3.1\100=0.031](https://tex.z-dn.net/?f=a%3D51%2C965%2C000%5C%5Cr%3D3.1%5C%25%3D3.1%5C100%3D0.031)
substitute
![P(t)=51,965,000(1+0.031)^t](https://tex.z-dn.net/?f=P%28t%29%3D51%2C965%2C000%281%2B0.031%29%5Et)
![P(t)=51,965,000(1.031)^t](https://tex.z-dn.net/?f=P%28t%29%3D51%2C965%2C000%281.031%29%5Et)
Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation
![P(5)=51,965,000(1.031)^5=60,534,681\ people](https://tex.z-dn.net/?f=P%285%29%3D51%2C965%2C000%281.031%29%5E5%3D60%2C534%2C681%5C%20people)
Step-by-step explanation:
Rate of drop of temperature = Change in temperature/Rate
=> (165 - 135)/15
=> 30/15
=> 2 ⁰F/min
Now, The time at which the temperature of will be 70⁰F = 70/Rate
=> 70/2
=> 35 min
Time for 110⁰ F
=> 110/2
=> 55 min
Answer:
The Normal distribution is a continuous probability distribution with possible values all the reals. Some properties of this distribution are:
Is symmetrical and bell shaped no matter the parameters used. Usually if X is a random variable normally distributed we write this like that:
![X \sim N(\mu , \sigma)](https://tex.z-dn.net/?f=%20X%20%5Csim%20N%28%5Cmu%20%2C%20%5Csigma%29)
The two parameters are:
who represent the mean and is on the center of the distribution
who represent the standard deviation
One particular case is the normal standard distribution denoted by:
![Z \sim N(0,1)](https://tex.z-dn.net/?f=Z%20%5Csim%20N%280%2C1%29)
Example: Usually this distribution is used to model almost all the practical things in the life one of the examples is when we can model the scores of a test. Usually the distribution for this variable is normally distributed and we can find quantiles and probabilities associated
Step-by-step explanation:
The Normal distribution is a continuous probability distribution with possible values all the reals. Some properties of this distribution are:
Is symmetrical and bell shaped no matter the parameters used. Usually if X is a random variable normally distributed we write this like that:
![X \sim N(\mu , \sigma)](https://tex.z-dn.net/?f=%20X%20%5Csim%20N%28%5Cmu%20%2C%20%5Csigma%29)
The two parameters are:
who represent the mean and is on the center of the distribution
who represent the standard deviation
One particular case is the normal standard distribution denoted by:
![Z \sim N(0,1)](https://tex.z-dn.net/?f=Z%20%5Csim%20N%280%2C1%29)
Example: Usually this distribution is used to model almost all the practical things in the life one of the examples is when we can model the scores of a test. Usually the distribution for this variable is normally distributed and we can find quantiles and probabilities associated
Answer:
This season
Step-by-step explanation:
Lowest Common Multiple (LCM) of 20 and 25 = 100
10/20 * 5/5 = 50/100 = 5/10
15/25 * 4/4 = 60/100 = 6/10
5/10 < 6/10
Hi!
I'm not sure how to slove this, but I do know how to solve it ;D
<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>
![\frac{x+y}{z*z}=3*z](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2By%7D%7Bz%2Az%7D%3D3%2Az)
x + y = 3 * z
<h3>Now subtract x from both sides.</h3>
x - x + y = 3 * z - x
<u>y = 3 * z - x</u>
<h2>The answer is y = 3 * z - x</h2>
Hope this helps! :)
-Peredhel