Answer:
<h3> (f/g)(x) = 4x³ - 8x - 5</h3>
<h3>(f/g)(2) = 11</h3>
Step-by-step explanation:
f(x) = 4x⁴ + 4x³ - 8x² - 13x - 5
g(x) = x + 1
To find (f/g)(2) first find (f/g)(x)
To find (f/g)(x) factorize f(x) first
That's
f(x) = 4x⁴ + 4x³ - 8x² - 13x - 5
f(x) = ( x + 1)( 4x³ - 8x - 5)
So we have
Simplify
We have
<h3> (f/g)(x) = 4x³ - 8x - 5</h3>
To find (f/g)(2) substitute 2 into (f/g)(x)
That's
(f/g)(2) = 4(2)³ - 8(2) - 5
= 4(8) - 16 - 5
= 32 - 16 - 5
= 11
<h3>(f/g)(2) = 11</h3>
Hope this helps you
Answer:
17/25
Step-by-step explanation:
sorry if I'm wrong
lay them out on.a piece of paper and circle every multiple of 2
Answer:
3
Step-by-step explanation:
Given the data: 7 6 5 9 3 4 7 9 5 8
INTERQUARTILE RANGE (IQR) = Q3 - Q1
Rearranging the data: 3, 4, 5, 5, 6, 7, 7, 8, 9, 9
Q3 = 0.75(n+1)th term
Q3 = 0.75(10 + 1) th term
Q3 = 0.75(11)th term = 8.25th term
Taking the 8th term = 8
Q1 = 0.25(11)th term = 2.75th
Taking the average of the 8th and 9th term:
(5 + 5) / 2 = 10/2 = 5
Q3 - Q1 = (8 - 5) = 3
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
