Question

The perimeter of a rectangular house is 122fr the width is 5ft less than the length find the length and width

Answer 1

Length x width is my suggestion

Answer 2

Hello,

Let's w the width , l the length, p the perimeter.

w=l-5
p=2(l+w)=2(l+l-5)=4l-10

4l-10=122
==>4l=122+10
==>4l=132
==>l=132/4
==>l=33
So w=33-5=28

Proof:
2*(33+28)=2*61=122