The perimeter of a rectangular house is 122fr the width is 5ft less than the length find the length and width
2 answers:
Length x width is my suggestion
Hello,
Let's w the width , l the length, p the perimeter.
w=l-5
p=2(l+w)=2(l+l-5)=4l-10
4l-10=122
==>4l=122+10
==>4l=132
==>l=132/4
==>l=33
So w=33-5=28
Proof:
2*(33+28)=2*61=122
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