(12ab)(3t) = (12 · 3)(abt) = 36abt
Answer:
-5=x
Step-by-step explanation:
-30=5x+5
-25=5x
-5=x
Answer: " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________
mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
___________________________________________________
The correct answer is 1.
So, circle the 0 after the equals sign because the equation does not equal 0.
Anything raised by the power of 0 is 1.
This is known as the zero exponent rule :)
