Question

PLEASE HELP ASAP!!!

Answer 1

$\text{Plug in 3 to y and solve:}\\\\4(3)^3-20+9(3)^2+(25 \div5)\\\\4(27)-20+9(3)^2+(25 \div5)\\\\4(27)-20+9(9)+(25 \div5)\\\\4(27)-20+9(9)+5\\\\108-20+81+5\\\\88+86\\\\174\\\\\boxed{\text{A). 174}}$

Answer 2

Answer:

A) 174

Step-by-step explanation:

I'm assuming 4y3 is 4y³ and 9y2 is 9y²

4×3³-20+9×3²+(25÷5)=

4×3³-20+9×3²+5=

4×27-20+9×9+5=

108-20+81+5=

88+81+5=

169+5=

174

A) 174