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k0ka [10]
3 years ago
6

Given OSALE, solve for x. 3 3x + 4 5x-6 S 3 A

Mathematics
2 answers:
murzikaleks [220]3 years ago
5 0

Answer:

x=5

Step-by-step explanation:

The sides have to be equal length

3x+4 = 5x-6

Subtract 3x from each side

3x+4-3x = 5x-6-3x

4 = 2x-6

Add 6 to each side

4+6 = 2x-6+6

10 = 2x

Divide by 2

10/2 =2x/2

5 =x

vlabodo [156]3 years ago
5 0

Two parallel sides is 3x + 4 = 5x - 6

\bf \large  \longrightarrow \:   \: 3x \:  +  \: 4 \:   =  \: 5 x \:  - \:  6

\bf \large  \longrightarrow \:   \:6 \:  +  \: 4 \:  =  \: 5x \:  -  \: 3x

\bf \large  \longrightarrow \:   \:10 \:  =  \: 2x

\bf \large  \longrightarrow \:   \: \frac{10}{2}  \:  =  \: x \\

\bf \large  \longrightarrow \:   \:  \cancel\frac{10}{2}   \: \large \:  ^{5}  \:  =  \: x \\

\bf \large  \longrightarrow \:   \:x \:  =   \: 5

Option ( B ) is the correct answer.

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9(5x + 1) ÷ 3y
alexdok [17]

The expression obtained after solving the given expression is,\rm \frac{(15x+3)}{y}

<h3>What is a BODMAS rule?</h3>

For the Bracket, Order, Division, Multiplication, Addition, and Subtraction rules, BODMAS stands for Bracket, Order, Division, Multiplication, Addition, and Subtraction.

Given expression ;

9(5x + 1) ÷ 3y

Follow the BODMAS rule;

Step 1; Divide

\rm \frac{9(5x+1)}{3y} \\\\ \frac{3(5x+1)}{y} \\\\

Step 2; Multiply

\rm \frac{9(5x+1)}{3y} \\\\ \frac{(15x+3)}{y} \\\\

Hence the expression obtained after solving the given expression is,\rm \frac{(15x+3)}{y}

To learn more about the BODMAS rule, refer to brainly.com/question/23827397.

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4 0
2 years ago
A rectangle has an area of 182 square meters and a base of 14 meters. What is the height?
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Step-by-step explanation:

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Step-by-step explanation:

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There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select
Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

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Number of non-defective pens = 3

A.) number of defective pens selected :

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It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

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3.)

Since selection is done without replacement

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