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Kitty [74]
3 years ago
10

6 + (8 x 3) - 9 Enter the value

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

Hello, so the answer is 21.

Step-by-step explanation:

Okay so first we want to do it order, so the order you do it in is the order of PEMDAS which stands for  Parentheses, Exponents, Multiplication, Division , Addition and Subtraction.

So in this situation we have parenthesis, multiplication, subtraction and addition, so we start with the parenthesis, (8 x 3) which is 24. So then we move on to +6 (positive six) and -9 (negative 9) basically -9 minus 6 is -3.

Sooo now we have -3 and 24. The three is negative because -9 minus 6 is -3, and you have to put the sign of the bigger number.

Now, 24 minus 3 equals 21. So there we have it :)

Hope I helped!

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3 years ago
The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
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Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

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The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

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