Answer:
d = 185.26 meters
Explanation:
It is given that,
Launching angle of the projectile, 
Initial speed of the projectile, u = 48 m/s
Let at distance d the projectile hits the ground from the launch point. It is equal to range of the projectile. Its formula is given by :
Substituting all the values in above formula. So, we get :
d = 185.26 meters
So, the distance between the launch point and the point where it hits is 185.26 meters. Hence, this is the required solution.
If both waves have the same wavelength, then the amplitude of
their sum could be anything between 1 cm and 9 cm, depending
on the phase angle between them.
If the waves have different wavelengths, then the resultant is a beat
with an amplitude of 9 cm.
Explanation:
It is given that, the water from a fire hose follows a path described by equation :
........(1)
The x component of constant velocity, 
We need to find the resultant velocity at the point (2,3).
Let 
and 
Differentiating equation (1) wrt t as,
When x = 2 and
So,
Resultant velocity, 
v = 6.4 m/s
So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.
