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inessss [21]
3 years ago
8

Assume that in interstellar space the distance between two electrons is about 0.8 cm. The electric force between the two electro

ns is
Physics
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

F = 3.6 x 10⁻²⁴ N

Explanation:

The force of attraction or repulsion between two charges is given by the Coulomb's Law. Coulomb's Law states that:

F = kq₁q₂/r²

where,

F = Electric Force between electrons = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = Charge on electron = 1.6 x 10⁻¹⁹ C

r = distance between electrons = 0.8 cm = 0.008 m

Therefore,

F = (9 x 10⁹ N.m²/C²)(1.6 x 10⁻¹⁹ C)(1.6 x 10⁻¹⁹ C)/(0.008 m)²

<u>F = 3.6 x 10⁻²⁴ N</u>

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an incandescent lightbulb has an efficiency of 2.1% and a power of 60 w. how much light energy does the lighbulb produce in 1 se
AveGali [126]

Explanation:

Power output of the bulb:

0.021 × 60 W = 1.26 W

Energy produced by the bulb in 1 second:

E = Pt

E = (1.26 W) (1 s)

E = 1.26 J

Round as needed.

5 0
3 years ago
A 560-g squirrel with a surface area of 930cm2 falls from a 5.0-m tree to the ground. Estimate its terminal velocity. (Use a dra
bija089 [108]

Explanation:

Terminal velocity is given by:

v_t=\sqrt{\frac{2mg}{\rho C_dA}}

Here, m is the mass of the falling object, g is the gravitational acceleration,  C_d is the drag coefficient, \rho is the fluid density through which the object is falling, and A is the projected area of the object. in this case the projected area is given by:

A=\frac{A_s}{2}=\frac{930cm^2}{2}=465cm^2\\465cm^2*\frac{1m^2}{10^4cm^2}=0.0465m^2\\560g*\frac{1kg}{10^3g}=0.56kg

Recall that drag coefficient for a horizontal skydiver is equal to 1 and air density is 1.28\frac{kg}{m^3}.

v_t=\sqrt{\frac{2(0.56kg)(9.8\frac{m}{s^2})}{(1.28\frac{kg}{m^3}(1)(0.0465m^2)}}\\v_t=13.58\frac{m}{s}

Without drag contribution the motion of the person is an uniformly accelerated motion, thus:

v_f^2=v_o^2+2gh\\v_f=\sqrt{2gh}\\v_f=\sqrt{2(9.8\frac{m}{s^2})(5m)}\\v_f=9.9\frac{m}{s}

7 0
3 years ago
How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?
slega [8]

The time the truck must apply the given force to increase its speed to given value is 5 s.

The given parameters;

  • <em>applied force, F = 600 N</em>
  • <em>mass of the truck, m = 1,500 kg</em>
  • <em>speed of the truck, v = 2 m/s</em>

The force applied to the truck is determined by Newton's second law of motion; <em>which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.</em>

F = ma

F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s

Thus, the time the truck must apply the given force to increase its speed to given value is 5 s.

Learn more here:brainly.com/question/1988795

7 0
3 years ago
An ideal battery would produce an extraordinarily large current if "shorted" by connecting the positive and negative terminals w
liubo4ka [24]

Answer:

Resistance, R=0.529\ \Omega

Explanation:

Given that,

Voltage of the battery, V = 9 volts

Current produced in the circuit, I = 17 A

We need to find the resistance when shorted by a wire of negligible resistance. It is a case of Ohm's law. The voltage is given by :

V=IR

R=\dfrac{V}{I}

R=\dfrac{9\ V}{17\ A}

R=0.529\ \Omega

So, the resistance in the circuit is 0.529 ohms. Hence, this is the required solution.

6 0
3 years ago
Which of the following correctly describes the importance of demonstrations to scientific investigation?
sergey [27]

Answer:

A- A demonstration shows how something works, often including models

Explanation:

A demonstration allows, through experimentation, to show how nature works and in that way can include the explanation of scientific theories that explain the set of observed facts, that is, it serves as a demonstration of the underlying scientific principles.

5 0
3 years ago
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