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spayn [35]
4 years ago
10

How do I simplify this?

Mathematics
1 answer:
chubhunter [2.5K]4 years ago
6 0
You can multiply each top and bottom by sqrt 15
then it will be 
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GivenAC ⊥ BD , complete the flowchart proof below. Note that the last statement and reason have both been filled in for you. ple
chubhunter [2.5K]

Answer:

Here you go!!!!! Its correct let me know if you need any more problems for me to try and solve!!!

Step-by-step explanation:

4 0
2 years ago
Look at the picture and answer pls!
Ray Of Light [21]

Answer:

its b I'm pretty sure........

7 0
3 years ago
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What is the ratio of 24 to 32
lubasha [3.4K]
It is 3 to 4
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6 0
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If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)
krok68 [10]

Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

<u>Step-by-step explanation:</u>

Here we have ,  sin ⁡x=7/25( given sin x = 725 which is not possible ) , 0 . Let's find tan (x - pi/4):

⇒ Tanx = \frac{sinx}{cosx}

⇒ Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}

⇒ Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}

⇒ Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}

⇒ Tanx = {\frac{7}{25}}(\frac{25}{24} )

⇒ Tanx = {\frac{7}{24}}

Now , Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}

⇒ Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24}  -1}{1+\frac{7}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )

⇒ Tan(x-\frac{\pi }{4}) = \frac{-17}{31}

7 0
4 years ago
8(3a+6)=2a-4
NISA [10]
A=-26/11 —> you will solve for a by simplifying both sides of the equation, then isolating the variable.
4 0
3 years ago
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