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4 years ago

Whats 3,465 in expanded form

Mathematics

1 answer:

dimulka [17.4K]4 years ago

7 0

3000 +400+60+5 is the answer.hope I helped you

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9 11/12- 2 8/11 is a problem that i need help on

Vitek1552 [10]

Hey there!!

Okay here are the steps you can follow!

9 11/12 ----> improper fraction ----> 119/12
2 8/11 ----> improper fraction ----> 30/11

119/12 - 30/11
(119/12 - 30/11) * 132
11(119) - 12(30)
1309 - 360
949

3 0

4 years ago

Describe how to model 65 + 12 on a number line.

Elina [12.6K]

draw the number line start with 65 then draw like semicircles going farther up the line and draw one big then write +10 and draw a small saying +2

8 0

4 years ago

Find the base of a triangles in

Alexus [3.1K]

The base of triangle is 24 inches whose area is 2.75 sq. feet

Solution:

Given, area of a triangle is 2.75 square feet and its height is 33 inches.

We have to find its base length in inches.

So let us convert area units from feet to inches.

Area = 2.75 square feet = 2.75 $\times$ ft $\times$ ft

= 2.75 $\times$ 12 inches $\times$ 12 inches

[since 1 foot = 12 inches ]

= 2.75 x 144 $\times$ $in^2$

Area = = 396 $in^2$

Area of triangle is given as:

$\text {area}=\frac{1}{2} \times \text { base } \times \text { height }$

$\begin{array}{l}{396= \frac{1}{2} \times \text { base } \times 33} \\\\ {2 \times 396=\text { base } \times 33} \\\\ {792=\text { base } \times 33} \\\\ {\text { Base }=\frac{792}{33}=24}\end{array}$

Hence, the base of the triangle is 24 inches

5 0

3 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> $a^7 = 128$

=> $a = \sqrt[7]{128}\\ \\\\a = 2$

For the second term:

$a^6b = -224$

$b = \frac{-224}{a^6}$

$b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5$

Therefore, a = 2, b = 3.5

5 0

3 years ago

What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x

Vinil7 [7]

$x^{2}-3x-5=0 \\ \\ \Delta=(-3)^{2}-4*1*(-5)=9+20=29 \\ \\ \sqrt{\Delta} = \sqrt{29} \\ \\ x_{1}= \frac{3- \sqrt{29} }{2} \\ \\ x_{2}= \frac{3+ \sqrt{29} }{2}$

\\\ Ben

3 0

3 years ago

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