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miss Akunina [59]
3 years ago
6

Someone help me please

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0

Step-by-step explanation:

The slope of the line passing through two points is given by,

\frac{y2 - y1}{x2 - x1}

13)

\frac{(0 - y)}{(0 - 2)}  =  (\frac{ - 3}{2} )

\frac{ - y}{ - 2}  =  \frac{ - 3}{2}

y =  - 3

option D

14)

\frac{ ( - 3 - y)}{(1 + 5)}  =  \frac{ - 1}{6}

\frac{ - 3 - y}{6}  =  \frac{ - 1}{6}

- 3 - y =  - 1

- y =  - 1 + 3 = 2

y =  - 2

option C

15)

\frac{(y - 4)}{( - 5 + 1)}  =  \frac{1}{4}

\frac{y - 4}{ - 4}  =  \frac{1}{4}

- y + 4 = 1

- y = 1 - 4 =  - 3

y = 3

option B

16)

\frac{(y + 3)}{( - 4 - 3)}  =  \frac{ - 3}{7}

- (y + 3) =  - 3

y = 3 - 3 = 0

option C

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Step-by-step explanation:

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Helppp pt.5 plzzzzz​
Fiesta28 [93]

Answer: 60 cm²

Step-by-step explanation:

This is pretty simple, we know AB is 12 cm and DE is 4 cm. We know ABC has a total of 180 square centimeters. So...

12 ÷ 3 = 4

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The answer is 60 cm²

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6 0
2 years ago
F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
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Who can solve this please
Vladimir79 [104]

Answer:

Shape 1 = l×b

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Shape 2 = l×b

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Step-by-step explanation:

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Montano1993 [528]

Answer:

x = 2

Step-by-step explanation:

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6 0
3 years ago
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