The base (b) of the triangle is units. The height (h) of the triangle is units. The area of the triangle is square units.
2 answers:
Answer:
Option A. Base of the triangle is 3unita
Option B. Height of the triangle is 5units
Option B. Area of the triangle is 7.5units
Step-by-step explanation:
The question is incomplete and lacking appropriate diagram. Here is the complete question.
The base (b) of the triangle is _ units.
A) 3 B) 5 C) 8 D) 13
The height (h) of the triangle is units.
A) 3 B) 5 C) 8 D) 13
The area of the triangle is square units.
A) 5 B) 7.5 C) 15 D) 30
Also find the attachment below.
From the graph, each square box in the graph will be taken as 1unit.
Since the base of the triangle is sitting on 3-square boxes, the total units of its base will be 3units. The base of the triangle is therefore 3units.
Similarly, the height of the triangle covers 5 square boxes, therefore the height of the triangle will be 5units.
Area of the triangle = 1/2 × base × height
Area of the triangle = 1/2 × 3 × 5
Area of he triangle = 15/2 = 7.5units
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Using a system of equations, it is found that:
- For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
- For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
- For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.
--------------------
The variables of the system are:
- x, which is the number of $29 tickets sold.
- y, which is the number of $34 tickets sold.
Total of 8,000 seats, all can be sold, thus:
--------------------
For a profit of $255,000, we have that:
For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
--------------------
For a profit of $271,000, we have that:
For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
--------------------
For a profit of $235,000, we have that:
For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.
A similar problem is given at brainly.com/question/22826010
For this case we have the following system of equations:
When solving the problem graphically we must take into account the following:
1) The solution of the system of equations is given by the intersection of both functions.
2) The solution is an ordered pair of the form (x, y)
For this case we observe that the solution is given by:
Note: see attached image.
Answer:
The approximate solution to the system is (1.23, 4.39)
When solving the problem graphically we must take into account the following:
1) The solution of the system of equations is given by the intersection of both functions.
2) The solution is an ordered pair of the form (x, y)
For this case we observe that the solution is given by:
Note: see attached image.
Answer:
The approximate solution to the system is (1.23, 4.39)