Let the 3-digit palindrome be 101a+10b. a+a+ab=8+b, so 2a+ab-b=8.
2a+b(a-1)=8; b=2(4-a)/(a-1). From this we know that a > 1. And we know 4-a > 0 so a < 4.
This limits a to 2 and 3 which make b=4 and 1.
The palindromes are 242 and 313.
I believe it would be y=-1/3x-2
(p+1) (p-1). solved this on paper . hope it helps .
Solve each system using a matrix
7x+2y=5
13x+14y=-1Solve each system using a matrix
7x+2y=5
13x+14y=-1
Answer:
-2
Step-by-step explanation:
Add them up: -14
Divide by how many there are: -14 / 7 = -2
