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weeeeeb [17]
2 years ago
13

Find the slope of the line passing through the points (-9, -2) and (5,-2).

Mathematics
1 answer:
alexandr402 [8]2 years ago
3 0

Answer:

0

Step-by-step explanation:

(x₁ , y₁) = (-9, -2)

(x₂ , y₂) = ( 5 , -2)

In these two points, there is no change in the y co-ordinates. So the line is parallel to x-axis.

slope of line parallel to x-axis = 0

         

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"Triple a number is 18."<br> Show all work
Marina86 [1]

Answer: 6

Step-by-step explanation:

3x = 18

Divide 18 by 3

x = 6

5 0
2 years ago
Read 2 more answers
Can someone please answer. There is one problem. There's a picture. Thank you!!!
djverab [1.8K]
The answer for your question is C. The reason is I multipled 15 and 6 which gave me 90 and that is closest to the answer C which is 72.73. Hope this helps:)
3 0
3 years ago
Choose all options that are expressions 6+5w 3-16v 4v+1 2v=0 18=v 7-v
Nataly [62]

Answer:

The expressions here are;

6 + 5w

3-16v

4v+ 1

7-v

Step-by-step explanation:

Here, out of the given set, we want to choose all options that are expression.

To do this, we should understand that expressions do not have the equality sign like equations

So expressions are those in the set in which we do not have an equality sign

The right answer is thus;

6 + 5w

3-16v

4v + 1

7-v

8 0
3 years ago
A computer maker receives parts from three suppliers, S1, S2, and S3. Fifty percent come from S1, twenty percent from S2, and th
rewona [7]

Answer:

a) 4.9 % of all parts is defective or 0.049 of the total parts.

b)  0.5102 is the probability that the defective part was supplied by S1

Step-by-step explanation:

N is the total number of parts from supplier S1, S2 and S3.

N1 = 0.5*N is the total number of part supplied by S1

N2 = 0.2*N is the total number of part supplied by S2  

N3 = 0.3*N is the total number of part supplied by S3

a) if Nd1 is the number of defective parts from supplier S1, Nd2 is the number of defective parts from supplier S2 and Nd3 is the number of defective parts from supplier S3, the the total defective parts Nd is:

Nd = Nd1 + Nd2 + Nd3, where

Nd1 = 0.05*N1 = 0.05*0.5*N = 0.025*N,

Nd2 = 0.03*N2 = 0.03*0.2*N = 0.006*N,

Nd3 = 0.06*N3 = 0.06*0.3*N = 0.018*N,

Then Nd = Nd1 + Nd2 + Nd3 =  0.049*N, so Nd/N = 0.049

b) P(S1 \vert d) = \frac{P(S1,d)}{P(d)} = \frac{P(d \vert S1)}{P(d)} = \frac{0.05*0.5}{0.049} \approx 0.5102

for the last expression I used the Bayes tehorem.

P(S1 \vert d) is the probability that occur S1 given that d (defective) is true. This a conditional probability.

see at https://en.wikipedia.org/wiki/Bayes%27_theorem

6 0
3 years ago
What is 4 1/2× 5<br>18 3/4 ×11×5
kolezko [41]
128390 5/8 or 128390.625

3 0
3 years ago
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