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weeeeeb [17]
2 years ago
13

Find the slope of the line passing through the points (-9, -2) and (5,-2).

Mathematics
1 answer:
alexandr402 [8]2 years ago
3 0

Answer:

0

Step-by-step explanation:

(x₁ , y₁) = (-9, -2)

(x₂ , y₂) = ( 5 , -2)

In these two points, there is no change in the y co-ordinates. So the line is parallel to x-axis.

slope of line parallel to x-axis = 0

         

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What is the equaiton of the line that goes through the point (6,-1) and is parallel to the line represented by the equautions y=
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parallel lines have the same slope


The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"


They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3


You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6


So far we have y=-5/6x + b

We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"


Replace that on the equation y=-5/6x + b and you get

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We found b, or the y-intercept


Go back to the equation y = -5/6 x + b and replace this b with the b we just found


y = -5/6x + 4

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