Answer: $1,540.00 is the total amount needed for the class trip
Step-by-step explanation:
Data: $110.00 earned for class trip
14th of the money needed
Money needed: x
<u>Step one, Make the equation</u>
110x14=x
Reason: Since we know 110.00 is a 14th of the money needed, we know multipling it by 14 will get us the money needed for the class trip. Having it in an equation will make it easier to solve.
<u>Step two, Evaluate the equation</u>
110x14=x=1540=x
Reason: The only thing that was left to do was to multiply 110 by 14 to get 1540 since the x was already isolated to begin with. That leaves us with the answer of x=1540.
However, since this is a real world problem, we have to make the answer more realistic so the final answer is '$1,540.00 is the total amount needed for the class trip'
I hope this helps!
Answer:
3.07
Step-by-step explanation:
The zeros of the function also called the roots are the x-intercepts where the function crosses the x-axis. The zeros are the x-values at these points. To find them, graph the function and look closely around the x-axis for intercepts.
See attached picture.
Answer:
17150 ft²
Step-by-step explanation:
Given the ratio of sides = a : b , then
ratio of areas = a² : b²
Here ratio of sides = 175 : 40 = 35 : 8 , then
ratio of areas = 35² : 8² = 1225 : 64
let x be the area of AT & T Stadium then by proportion
= ( cross- multiply )
64x = 896 × 1225 = 1097600 ( divide both sides by 64 )
x = 17150
The AT & T screen has an area of 17150 ft²
Answer:
x = 6.6
Step-by-step explanation:
Data obtained from the question include the following:
Angle X = 15°
Angle Y° = 23°
Side y = 10
Side x =..?
The value of side x can be obtained by using the sine rule as shown below:
x/Sine X = y/Sine Y
x/Sine 15 = 10/Sine 23
Cross multiply
x × Sine 23 = 10 × Sine 15
Divide both side by Sine 23
x = (10 × Sine 15) / Sine 23
x = 6.6
Therefore, the value of x is 6.6.