Question

Becky drew a scale drawing of a sign before creating it. Her scale drawing had a width of 6 inches, and the actual sign has a width of 4 feet. What is the scale factor?

Answer 1

Answer:

$4ft *\frac{12in}{1 ft}= 48 in$

Now since we have the same units for the scale model and the real one we can find the scale factor like this:

$Scale = \frac{48 in}{6in}= 8$

And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model

Step-by-step explanation:

For this problem we know that the scale model had a widthof 6 inches. And the actual model has a width of 4ft. First we need to convert the 4ft to inches and we got:

$4ft *\frac{12in}{1 ft}= 48 in$

Now since we have the same units for the scale model and the real one we can find the scale factor like this:

$Scale = \frac{48 in}{6in}= 8$

And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model