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3 years ago

How do you find the area

Mathematics

2 answers:

natima [27]3 years ago

5 0

To find the area of a parallelogram is just like trying to find the area of a square: b*h.
12*8 = 96.
The figure is 96 square meters.

Hope this helped,
Loafly

Serjik [45]3 years ago

4 0

Remember Length*width*height

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If (x - 4) varies inversely as (y + 3) and x = 8 when y = 2, what is x when y = - 1?

denpristay [2]

Answer:

$x=14$

Step-by-step explanation:

If two values are inversely proportional, their product must be maintained. That way, if one value goes up, the other goes down by the same extent.

Therefore, if $(x-4)$ and $(y+3)$ vary inversely, their product will be the same for all values of $x-4$ and $y+3$ .

Let $x=8$ and $y=2$ as given in the problem. Substitute values:

$(8-4)(2+3)=(4)(5)=20$

Hence, the maintained product is $20$ .

Thus, we have the following equation:

$(x-4)(y+3)=20$

Substitute $y=-1$ to find the value of $x$ when $y=-1$ :

$(x-4)(-1+3)=20,\\(x-4)(2)=20,\\x-4=10,\\x=10+4=\boxed{14}$

3 0

2 years ago

i’m order for a graph to be proportional it must cross through the origin. A.true B.false

Gelneren [198K]

Answer:

True

Step-by-step explanation:

Key idea: the graph of a proportional relationship is a straight line through the origin.

8 0

3 years ago

Read 2 more answers

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

4 0

3 years ago

What additional information is needed to prove the triangles are congruent by the SAS Postulate?

Kitty [74]

You need to know the length of two sides and the degree of one angle.

7 0

3 years ago

Cleo won 75% of the games he pitched. If he won 30 baseball games, how many games did he pitch?

Free_Kalibri [48]

Answer:

Step-by-step explanation:

75% divided by 3 since its 3/4 of 100

do the same to 30

7 0

3 years ago