Could someone please help me with 1 and 2 please
1 answer:
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Answer:
2π or 0π are the only points that satisfy the expression, but since the restriction is 0 <= x < 2π
the answer would be 0π
The sum of the given series can be found by simplification of the number
of terms in the series.
- A is approximately <u>2020.022</u>
Reasons:
The given sequence is presented as follows;
A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021
Therefore;
The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;
Therefore, for the last term we have;
2 × 2043231 = n² + 3·n + 2
Which gives;
n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0
Which gives, the number of terms, n = 2020
Which gives;
- A ≈ <u>2020.022</u>
Learn more about the sum of a series here: