The sum of the first n terms of sequence 85 +85(.9) +85(.9)² + ... would be 348.08.
<h3>What is the sum of terms of a geometric sequence?</h3>
Let's suppose its initial term is a , multiplication factor is r and let it has total n terms,
then, its sum is given as:
(sum till nth term)
Given geometric sequence;
85 +85(.9) +85(.9)² + ...
a = 85
r = 0.9
its sum is given as:
Thus,
The sum of the first n terms of sequence 85 +85(.9) +85(.9)² + ... would be 348.08.
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so you have
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If you don't remember the value of off the top of your head, it's possible to derive it with some identities and knowing that .
Consider the expression . With the angle sum identity, we have
and the double angle identities give
Write everything in terms of cosine:
Now let . Then
Let . Then
The rational root theorem suggests some possible roots are
and checking all of these, we find that is among the solution set. In fact,
We have only for odd multiples of , so it follows that
Answer:
12
Step-by-step explanation:
By ythagoras Theorem,
x^2 + 9^2 = 15^2
x^2 + 81 = 225
x^2 = 225 - 81
x^2 = 144
x = √144
x = 12
Answer:
all you need to do is multiply all of the numbers together.
Step-by-step explanation:
Ym=(Y1+Y2)/2
Ym=(-9+-64)/2=-36.5
The midpoint is: (51.5,-36.5)