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3 years ago

Simplify radical -50

Mathematics

2 answers:

sesenic [268]3 years ago

8 0

Answer:

$5i\sqrt{2}$

Step-by-step explanation:

If we want to convert $\sqrt{-50}$ into a radical simplified, we need to find two numbers that multiply to be -50 and one of them can be squared.

$\sqrt{-50} = \sqrt{-25 \cdot 2}$

The square root of -25 is 5i.

So:

$5i\sqrt{2}$

Hope this helped!

Anestetic [448]3 years ago

4 0

Answer: $=5i\sqrt{2}$

Step-by-step explanation:

$\sqrt{-50}=\sqrt{-1}\sqrt{50}$

$\sqrt{-1}\sqrt{50}$

$\sqrt{5^2\cdot \:2}$

$=\sqrt{2}\sqrt{5^2}$

$\sqrt{5^2}=5$

$=5\sqrt{2}$

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A.)

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$\begin{aligned}
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If $\sin^2 (x) + \cos^2(x) = 1$ then subtracting both sides by $\cos^2 (x)$ yields $\sin^2(x) = 1 - \cos^2(x)$ . We can substitute that into the numerator

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======

b.)

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$\begin{aligned}
\text{LHS} &= \dfrac{\sec(x)}{\cos(x)} - \dfrac{\tan(x)}{\cot(x)} \\
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Since $\cot (x) = \cos (x) / \sin (x)$

$\begin{aligned} \text{LHS} &= \frac{1}{\cos^2 (x)} - \frac{1}{\frac{\cos^2(x)}{\sin^2(x)} } \\ &= \frac{1}{\cos^2 (x)} -\frac{\sin^2(x)}{\cos^2(x)} \\ &= \frac{1 - \sin^2(x)}{\cos^2 (x)} \end{aligned}$

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