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Anestetic [448]
3 years ago
7

Help me.... need help

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Answer:what grade u in


Step-by-step explanation:


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Help meeeeeeeeeeeee<br><br><br><br><br><br>2/3u. 4/2u².3=<br>​
Firdavs [7]

Answer:

4u³

Step-by-step explanation:

2/3u × 4/2u² = 4/3u³

4/3u³ × 3/1 = 4u³

6 0
3 years ago
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Belinda wants to invest in an option that would help to increase your investment value by the greatest amount in 20 years. Will
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Step-by-step explanation:

Part A, Option 1 is a exponential function while option is a linear equation.

Part B, Let y=b*a^(x) be the function for option 1. At x=1, y=1100 and at x=2, y=1210. 1100=b*a and 1210=b*a^2. Dividing them both we get, b=1.1 and a=1000. y=1000*(1.1)^(x). For option 2, it's a linear equation with a function y(x)=1000+100x.

The 20 year difference would be immense. With option 1, Belinda will get $6727.5 whereas with option 2, they will end up with $3000

5 0
3 years ago
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What is answer please
Tanzania [10]

Answer:

during the first 3mins the bus was accelerating from 0km to 25 kilometers

during the next 90 mins btwn 30mins to 120 mins it was moving at a constant distance n speed

lastly for the last 60 mins from 120 mins to 180 mins it started decelerating from a distance of 25km to 0 km

8 0
3 years ago
The Company with the highest percentage of sales revenue from sedans is ________. The relative frequency of the revenue earned b
navik [9.2K]
the firt answer is Allison and the second answer is0.34
4 0
3 years ago
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What are the roots of x cubed - 7*x squared + 13x-6
Natalka [10]

The roots of x^3 - 7x^2 + 13x - 6 are 0.697, 2 and 4.303

<h3>How to determine the roots?</h3>

The expression is given as:

x^3 - 7x^2 + 13x - 6

Express as a function

f(x) = x^3 - 7x^2 + 13x - 6

Next, we plot the graph of the function f(x) (see attachment)


From the attached graph, we have the zeros to be:

x = 0.697, 2 and 4.303

Hence, the roots of x^3 - 7x^2 + 13x - 6 are 0.697, 2 and 4.303

Read more about roots at:

brainly.com/question/20896994

#SPJ1

5 0
2 years ago
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