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Stells [14]
3 years ago
12

If the ratio of dogs to cats at an animal shelter is 2:5, then the number of cats is _____ times the number of dogs. CHECK

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0
The number of cats is 2.5 times the number of dogs.
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6.66 barred..........
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3 years ago
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The average wage for an electrician in CA is $25.47/hour. That is 11% above the national average. What is the national average?​
yan [13]

Answer:

$22.95/hour.

Step-by-step explanation:

It is given that the average wage for an electrician in CA is $25.47/hour. That is 11% above the national average.

Let as consider x be the national average.

11% above the national average is

x+\dfrac{11}{100}x=x+0.11x=1.11x

The average wage for an electrician in CA is 11% above the national average. So,

1.11x=25.47

Divide both sides by 1.11.

x=\dfrac{25.47}{1.11}

x=22.945945...

x=22.95

Therefore, the national average is $22.95/hour.

3 0
3 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
Which expression represents the distance between 4.7 and −11.2 on the number line?
Cerrena [4.2K]

Answer:

4.7 - ( -11.2)

Step-by-step explanation:

4.7 - ( - 11.2) = 15.9  

15.9 is the distance between 4.7 and -11.2

Hopefully this helps you

pls mark brainlest

3 0
3 years ago
Please help this question.
sergejj [24]

Answer:

a). 59.049°C

b). 2.1179 seconds

Step-by-step explanation:

Expression representing the final temperature after decrease in temperature of the metal from 100°C to T°C is,

T = 100(0.9)^{x}

where x = duration of cooling

a). Temperature when x = 5 seconds

T = 100(0.9)⁵

  = 59.049

  ≈ 59.049°C

b). If the temperature of the metal decreases from 100°C to 80°C

Which means for T = 80°C we have to calculate the duration of cooling 'x' seconds

80 = 100(0.9)^{x}

0.8 = (0.9)^{x}

By taking log on both the sides

log(0.8) =log[(0.9)^{x}]

-0.09691 = x[log(0.9)]

-0.09691 = -0.045757x

x = \frac{0.09691}{0.045757}

x = 2.1179

x ≈ 2.1179 seconds

3 0
3 years ago
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