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MakcuM [25]
4 years ago
11

In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11?

Mathematics
1 answer:
vova2212 [387]4 years ago
6 0

Answer:

{ x ∈ R | x ≥  9 }

Step-by-step explanation:

we have

2x-7 \geq 11

solve for x

Adds 7 both sides

2x\geq 11+7

2x\geq 18

Divide by 2 both sides

x\geq 18/2

x\geq 9

The solution is the interval -----> [9,∞)

In set builder notation

{ x ∈ R | x ≥  9 }

All real numbers greater than or equal to 9

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