Question

In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11?

Answer 1

Answer:

{ x ∈ R | x ≥  9 }

Step-by-step explanation:

we have

$2x-7 \geq 11$

solve for x

Adds 7 both sides

$2x\geq 11+7$

$2x\geq 18$

Divide by 2 both sides

$x\geq 18/2$

$x\geq 9$

The solution is the interval -----> [9,∞)

In set builder notation

{ x ∈ R | x ≥  9 }

All real numbers greater than or equal to 9