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Dahasolnce [82]
3 years ago
9

Which of the following is true about the function y= 4 * 3tothepowerofx

Mathematics
1 answer:
xenn [34]3 years ago
8 0

Only true statement for function f(x) = 4(3^{x}) is <u>c.  if the value of x increases by 1, the value of y will triple</u>.

<u>Step-by-step explanation:</u>

<u>a.  the function decreases </u>

f(x) = 4(3^{x}) , For value of x<1 function decreases and for x>1 function increases . False statement .

<u>c.  if the value of x increases by 1, the value of y will triple. </u>

For value of x increases by 1 we have , f(x) = 4(3^{x+1}) = 4(3^{x})(3) = f(x) (3) = y(3) . True statement.

<u>b.  the function has a y-intercept of (0, 3) </u>

At y intercept x=0, f(x) = 4(3^{x}) , f(0) = 4(3^{0}) = 4 . Function has a y-intercept of (0,3). False statement.

<u>d.  the function contains the point (1, 4)</u>

At x=1, f(1) = 4(3^{1}) = 12 . Function contains (1,12) not (1,4) . False statement.

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Marianna [84]
X^2 -  13 x = -36 
add 36 to both sides

x^2 - 13x +36 = 0
figure out the factor
(x-4)(x-9) = 0
so (x-4) or (x-9) equals 0
so solution is
x-4=0 add 4 to both sides and get x = 4
x-9=0 add 9 to both sides and get x=9
x={ 4, 9}
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3 years ago
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
-Dominant- [34]

Answer: 0.0031

Step-by-step explanation:

Binomial distribution formula :-

P(x)=^nC_xp^x(1-p)^{n-x}, where P(x) is the probability of x successes in the n independent trials of the experiment and p is the probability of success.

Given : A binomial probability experiment is conducted with the given parameters.

n=9,\ p=0.8,\ x\leq3

Now, P(x\leq3)=P(3)+P(2)+P(1)+P(0)

=^9C_3(0.8)^3(1-0.8)^{9-3}+^9C_2(0.8)^2(1-0.8)^{9-2}+^9C_1(0.8)^1(1-0.8)^{9-1}+^9C_0(0.8)^0(1-0.8)^9\\\\=\dfrac{9!}{3!6!}(0.8)^3(0.2)^6+\dfrac{9!}{2!7!}(0.8)^2(0.2)^7+\dfrac{9!}{1!8!}(0.8)(0.2)^8+\dfrac{9!}{0!9!}(0.2)^9=0.003066368\approx0.0031

Hence,  P(x\leq3)=0.0031

8 0
4 years ago
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3 years ago
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The <em><u>correct answer</u></em> is:

AAS

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In these triangles, we have ∠CAB ≅ ∠CDB given to us to begin with.  Throughout the proof, we find that ∠ABC ≅ ∠DCB.  We also have that CB is congruent to itself.  This is two angles and a side not included, so this is AAS.

4 0
3 years ago
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4 0
3 years ago
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