Answer : Option C) 0.129 J/g°C
Explanation : The given information has about Q which is heat energy (3,000 J);
m is the mass of a substance (0.465 kg);
∆T is the measure for the change in temperature (100 - 50) = 50°C;
To find the specific heat of the given unknown substance, we have to use the formula as;
q = m x C x ∆T; where c is the specific heat;
So, substituting the above values in this equation we get;
C = q/ (m x ∆T)
Therefore, it will be C = 3000 / (0.465 X 50) = 129.0 J/Kg°C
But we want the answer in grams, not in kilograms;
So, it will be 129.0 / 1000 = 0.129 J/g°C
Therefore, the specific heat of the unknown substance is 0.129 J/g°C
