Answer:
The smallest particle of a chemical element can be defined as an atom.
Explanation:
The number of protons in one atom of an element determines the atom's identity, and the number of electrons determines its electrical charge.
a single electron or one of two or more electrons in the outer shell of an atom that is responsible for the chemical properties of the atom is known as valence electrons.
An atom's reactivity is its tendency to lose or gain electrons. ... This is because they have one outer electron and losing it gives them the stability of a outer electron shell as the next level... The reactivities of elements can be predicted by periodic trends.
1500 mm of copper wire are produced by converting 150 cm of copper wire.
The following is the centimeter to millimeter conversion factor: 1 cm is equivalent to 10 mm.
Consequently, 150 cm will equal 150 x 10 = 1500 mm.
- The multi-step process of unit conversion involves multiplying or dividing by a numerical factor.
- Unit conversion is the process of converting the measurement of a given amount between various units, often by multiplicative conversion factors that alter the value of the measured quantity without altering its effects.
- Unit conversion is a multi-step procedure that involves adding, subtracting, multiplying, or dividing by a conversion factor.
- The process may also require the selection of the correct number of significant digits, and rounding.
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Answer:
D) 2, 4, and 5
Explanation:
In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.
If heat is absorbed in a reaction, that reaction is endothermic.
Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.
Answer:
E = 3.81×10 ⁻²¹ J
Explanation:
Given data:
Frequency of photon = 5.75 ×10¹² Hz
Plancks constant = 6.626 ×10⁻³⁴ Js
Energy of photon = ?
Solution:
E = h×f
E = 6.626 ×10⁻³⁴ Js × 5.75 ×10¹² s⁻¹
E = 38.1×10 ⁻²² J
E = 3.81×10 ⁻²¹ J
