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vlada-n [284]
3 years ago
13

Do you believe the research subjects in the original study were appropriate for this experiment

Chemistry
2 answers:
olga55 [171]3 years ago
5 0
Umm......in what study?
ioda3 years ago
4 0
Fgdgdfgdfgdfgdfgfdgfsdasffglkjhuifgnufgu

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After an investigation, what do scientists often do?
den301095 [7]
Record observations, pose a question, create a test for an individual variable, test, come to a conclusion
7 0
3 years ago
The molecular formula for butane is C4H10. Determine the percent composition for
masya89 [10]

%Mass

Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol

\tt C=\dfrac{4.12}{58}\times 100\%=82.8\%\\\\H=100\%-82.8\%=17.2\%

or

\tt H=\dfrac{10.1}{58}\times 100\%= 17.2\%

4 0
2 years ago
Mg+o2 balanced eaquation
Tanya [424]

Answer:

2Mg+O2=2MgO

balanced equation

hope it helps.

5 0
3 years ago
Read 2 more answers
40o+2 protons electrons And neurons
KatRina [158]

Answer: There are few simple rules to follow.

(1) The atomic number is equal to the number of protons.

Z

= number of protons

(2) In neutrally charged elements, the number of electrons is the same as the number of protons.  

Z

= number of protons = number of electrons (no charge)

Otherwise, positive charge means that the element lost an electron and negative charge means it gained an electron.

(3) The atomic mass is equal to the sum of the number of protons and number of neutrons.

A

= number of protons + number neutrons  

or

A

=  

Z

+ number neutrons

So if you say that  

Z

= 20 and  

A

= 40, then

A

=  

Z

+ number neutrons

40 = 20 + number of neutrons

40 - 20 = number of neutrons

Therefore,

number of neutrons = 20

Explanation:

7 0
3 years ago
How many moles make up 5.7491x1025 molecules of Dinitrogen pentoxide (N2O5)?
pav-90 [236]

Answer:

<h2>95.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.7491 \times  {10}^{25} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>95.5 moles to 3 sig. figures</h3>

Hope this helps you

6 0
3 years ago
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