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goldfiish [28.3K]
3 years ago
10

The substitution method solve 6x-y=3 4x+3y=1

Mathematics
2 answers:
bekas [8.4K]3 years ago
8 0

Answer:

<h2> </h2><h2>( \frac{5}{11}  \:,  -  \frac{3}{11} )</h2>

Step-by-step explanation:

6x - y = 3

4x + 3y = 1

Solve the equation for y

y = -3 + 6x

4x + 3y = 1

Substitute the given value of y into the equation

4x + 3y = 1

plug the value

4x + 3( - 3 + 6x) = 1

Distribute 3 through the parentheses

4x  - 9 + 18x = 1

Collect like terms

22x - 9 = 1

Move constant to R.H.S and change its sign

22x = 1 + 9

Calculate the sum

22x = 10

Divide both sides of the equation by 22

\frac{22x}{22}  =  \frac{10}{22}

Calculate

x =  \frac{5}{11}

Now, substitute the given value of x into the equation

y = -3 + 6x

y =  - 3 + 6 \times  \frac{5}{11}

Solve the equation for y

y =  -  \frac{3}{11}

The possible solution of the system is the ordered pair ( x , y )

<h2>(x ,\: y) = ( \frac{5}{11}  ,\:  -  \frac{3}{11} )</h2>

-----------------------------------------------------------

Check if the given ordered pair is the solution of the system of equations

6 \times  \frac{5}{11}  - ( -  \frac{3}{11} ) = 3

4 \times  \frac{5}{11 }  + 3 \times ( -  \frac{3}{11} ) = 1

Simplify the equalities

3 = 3

1 = 1

Since all of the equalities are true , the ordered pair is the solution of the system

<h2>( \: x ,\: y \: ) = ( \frac{5}{11}  \:,  -  \frac{3}{11} )</h2>

Hope this helps..

Best regards!!

Juli2301 [7.4K]3 years ago
5 0
Y= - 3 + 6x
4x+3y=1
4x+3(-3 + 6x) = 1
4x-9+18x-1=0
22x= 0
22x= -8
x = -8/22 = -4/11
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Answer:

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Step-by-step explanation:

The complete question is:

Suppose that a computer chip company has just shipped 10,000 computer chips to a computer company. Unfortunately, 50 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) There are 50 defective chips out of 10,000 shipped. The probability that the first chip randomly selected is defective is  50 /10,000  = 0.005.  Compute the probability that two randomly selected chips are defective under the assumption of independent events.

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