Atomic radius is the distance from the nucleus to the last valance electron up to which the effect nucleus can be felt. The size of the atom depends on the Electrostatic interaction between nucleus and electron. Number of atomic orbitals present. With the increase in numbers of orbitals down the group the size of the atom increases. Again, as the numbers of electrons increases in the period ,the electrostatic interaction between nucleus and electron increases along the period. Therefore, size of atoms decreases along the period.
As expected the element with highest atomic radius is the last element of group 1 , Which is FRANCIUM ( Fr)
A. hydroxide is the answer
Kc = 3.2
The chemical equation is
2H2S ⇌ 2H2 + S2
The equilibrium constant expression is
<em>K</em>c ={[H2]^2[S2]}/[H2S]^2
1. Calculate the <em>equilibrium concentrations</em> of each component
[H2] = (4.0 mol)/(4.0 L) = 1.0 mol/L
[S2] = (0.80 mol)/(4.0 L) = 0.20 mol/L
[H2S] = (1.0 mol)/(4.0 L) = 0.25 mol/L
2. Calculate the value of the <em>equilibrium constant</em>
<em>K</em>c = (1.0^2 x 0.20)/0.25^2 = 3.2
I believe this would be an exothermic reaction, As time increases, the temperature goes up meaning the heat from the system is going into the surroundings. Which indicates an exothermic reaction.
Valence <span>electrons are the highest form</span>