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sveticcg [70]
3 years ago
15

The vapor pressure of a substance is measured over a range of temperatures. A plot of the natural log of the vapor pressure vers

us the inverse of the temperature (in Kelvin) produces a straight line with a slope of −3.58×103K.What is the enthalpy of vaporization of the substance?29.8 kJ/mol2.32×1023kJ/mol0.431 kJ/mol294 kJ/mol
Chemistry
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

ΔHvap = 431 J/mol

Explanation:

The relation between the vapor pressure and the absolute temperature is given by the Clausius-Clapeyron equation.

lnp=\frac{-\Delta Hvap}{R} .\frac{1}{T} +C

where,

p: vapor pressure

ΔHvap: enthalpy of vaporization

T: absolute temperature

C: constant

We can see that this corresponds to a linear equation with slope -ΔHvap/R and intercept C. If the slope is -3.58 × 10³ K,

-3.58 × 10³ K = -ΔHvap/R

3.58 × 10³ K = ΔHvap/(8.314 J/K.mol)

ΔHvap = 431 J/mol

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1) Answer is: there are 28 moles of hydrogen in 2.8 mol of caffeine.

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In one molecule of caffeine (C₈H₁₀N₄O₂) there are four nitrogen atoms:

n(C₈H₁₀N₄O₂) : n(N) = 1 : 4.

n(C₈H₁₀N₄O₂) = 0.4 mol; amount of the coffeine molecules.

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4) Answer is: there are 7 moles of oxygen in 3.5 mol of caffeine.

In one molecule of caffeine (C₈H₁₀N₄O₂) there are two oxygen atoms:

n(C₈H₁₀N₄O₂) : n(O) = 1 : 2.

n(C₈H₁₀N₄O₂) = 3.5 mol; amount of the coffeine molecules.

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n(O) = 3.5 mol · 2.

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