Answer:
CH₂O
Explanation:
From the question given above, the following data were obtained:
Carbon (C) = 39.9%
Hydrogen (H) = 6.7%
Oxygen (O) = 53.4%
Empirical formula =?
The empirical formula of acetic acid can be obtained as follow:
C = 39.9%
H = 6.7%
O = 53.4%
Divide by their molar mass
C = 39.9 / 12 = 3.3
H = 6.7 / 1 = 6.7
O = 53.4 / 16 = 3.3
Divide by the smallest
C = 3.3 / 3.3 = 1
H = 6.7 / 3.3 = 2
O = 3.3 / 3.3 = 1
The empirical formula => CH₂O
Answer:
for the reaction is -198.762 J/K
Explanation:
Standard change in entropy for the system () is given by-
![\Delta S^{0}=[2moles\times S^{0}(NH_{3})_{g}]-[1mole\times S^{0}(N_{2})_{g}]-[3\times S^{0}(H_{2})_{g}]](https://tex.z-dn.net/?f=%5CDelta%20S%5E%7B0%7D%3D%5B2moles%5Ctimes%20S%5E%7B0%7D%28NH_%7B3%7D%29_%7Bg%7D%5D-%5B1mole%5Ctimes%20S%5E%7B0%7D%28N_%7B2%7D%29_%7Bg%7D%5D-%5B3%5Ctimes%20S%5E%7B0%7D%28H_%7B2%7D%29_%7Bg%7D%5D)
where 
represents standard entropy.
Here 
, 
and 
So, ![\Delta S^{0}=[2\times 192.45]-[1\times 191.61]-[3\times 130.684]J/K=-198.762J/K](https://tex.z-dn.net/?f=%5CDelta%20S%5E%7B0%7D%3D%5B2%5Ctimes%20192.45%5D-%5B1%5Ctimes%20191.61%5D-%5B3%5Ctimes%20130.684%5DJ%2FK%3D-198.762J%2FK)
Answer:
chemicals symbols are used for abbreviating the name of the element/chemical while chemicals formulas tell you how much of each element are in each chemical atom
Explanation:
Halogen--Florine
Chalogen-- Oxygen
Alkali Metal-- Sodium
Boron -- Metalloid (atomic symbol B)
Lanthanide series-- (Number 57-71 on periodic Table) Example: Cerium #58
Alkaline Earth Metal--Magnesium
Transition Metal-- Gold, Iron, Silver. Etc... (Middle section of a period table)
Nobel Gas--Helium
