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Lena [83]
3 years ago
7

Using paper folding to construct a line perpendicular to a given line through a point

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer: upon itself

Step-by-step explanation: apex

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Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant
son4ous [18]
The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}
\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}

and

\dfrac{\mathrm dx}{\mathrm dt}=\cos t
\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t

Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}
\dfrac{\mathrm dw}{\mathrm dt}=\tan t
4 0
3 years ago
1400 dollars is placed in an account with an annual interest rate of 7.25%. To the nearest tenth of a year, how long will it tak
Vlad [161]

Answer:17

Step-by-step explanation:

6 0
3 years ago
The more hours maribel works at her job the larger her paycheck is . find the independent variable
Goshia [24]
Almost positive this answer is the amount of hours she would work. because if she worked more hours her outcome would be a larger paycheck and if she worked less hours her paycheck would be smaller.
8 0
3 years ago
What is 1 + 1 i need help.
Anastasy [175]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
the product of two consecutive integers n and n+1 is 42. what is the positive integer that satisfies the situation?
MrMuchimi
n(n+1)=42 \\
n^2+n=42 \\
n^2+n-42=0 \\ \\
a=1 \\ b=1 \\ c=-42 \\ b^2-4ac=1^2-4 \times 1 \times (-42)=1+168=169 \\ \\
n=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-1 \pm \sqrt{169}}{2 \times 1}=\frac{-1 \pm 13}{2} \\
n=\frac{-1 -13}{2} \ \lor \ n=\frac{-1+13}{2} \\
n=\frac{-14}{2} \ \lor \ n=\frac{12}{2} \\
n=-7 \ \lor \ n=6

The positive integer is 6.
The consecutive integers are 6 and 7.
8 0
3 years ago
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