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sesenic [268]
3 years ago
7

3. Cory is a door-to-door salesman for TV Bonanza Cable Company. The company offers cable television

Mathematics
1 answer:
nikitadnepr [17]3 years ago
6 0

Answer:

ai. $240

aii. $120

bi. $840

bii. $70

c. 120 + 60(x) = A

d. [120 + 60(x)]/x = M

Step-by-step explanation:

Please kindly see the attached for detailed explanation

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Se golpea (chuta) un balón sobre el piso y sale dando botes parabólicos cada vez menores. Si se lanzo inicialmente con una veloc
Ipatiy [6.2K]

Answer:

a)d = 180,91 m

b)t = 11,76 seg

Step-by-step explanation:

Para el lanzamiento de proyectil, la ecuación que nos da la velocidad en V(y) es:

V(y)  = Voy - g*t

en donde Voy = Vo * senα    ( donde Vo es la velocidad inicial, α el angulo del disparo.

Si en esta ecuación hacemos V(y) = 0 estamos en el punto donde el componente en el eje y de la velocidad del proyectil es cero, ese punto es el punto medio del recorrido.

0 =  Vo*sen 60⁰     - g*t

g*t  =  Vo* √3/2

t  = { 32 [m/s] * √3 }2*9,8 [m/s²]

t = 16*√3  / 9,8

t = 2,8278 seg

El tiempo total del primer recorrido es entonces por simetría

t₁ = 2 * 2,8278           t₁  = 5,6556 seg

La distancia del primer impacto al suelo es:

x = Vox * t₁                        ( Vox es constante   Vx = Vo*cos 60⁰ )

x  =  32 * (1/2) * 5,6556

x₁  =  90,49 m

Aplicando los mismos criterios ahora para el segundo bote

Ahora Vo = 32 -  32*(1/4)

V = 24 m/s

g*t  =  24 * sen 50⁰

t =  24* 0,7660/ 9,8  

t =  1,8759

2*t  = 2*1,8759

t₂  = 3,7518 seg

x₂  =  Vox * t₂

x₂  =  24* 0,6428*3,7518

x₂  =  57,88 m

Y para el tercer bote Vo =  24 - 24(1/4)        Vo = 18 m/s     α = 40⁰

t = 18 *0,6428/9,8

t  = 1,18

2t  = t₃  = 2*1,18

t₃ = 2,36 seg

x₃  = Vox * 2,36                Vox = Vo*cos 40      Vox = 18*0,7660  

Vox = 13,79

x₃  = 13,79*2,36

x₃  = 32,54 m

La distancia total será

d = x₁  + x₂ + x₃

d  =  90,49  + 57,88 + 32,54

d = 180,91 m

y el tiempo total será la suma de los tiempos

t =  t₁  +  t₂  +  t₃

t  = 5,65 + 3,75 + 2,36

t = 11,76 seg

8 0
3 years ago
one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt
In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

 \text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A

⇒ \text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A

= \frac{3-1}{3} A

= \frac{2}{3} A

\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B

⇒ \text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B

But, Again according to the question,

The total population that claims that they are from A =  one half of the total population of A and B.

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B

⇒ \frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B

⇒ \frac{1}{6} A = \frac{1}{4} B

⇒ A =\frac{6}{4}B

⇒ \frac{A}{B} =\frac{3}{2}

8 0
4 years ago
Find the sum of 18 + (-15).<br><br> A. 3<br><br> B. -3<br><br> C. 33<br><br> D. -33
Delvig [45]

Answer: 3

Step-by-step explanation: To find the sum of these two numbers, remember that adding a negative is exactly the same thing as subtracting a positive. In other words, when we see 18 + (-15), we can change the problem so it's easier to understand and we will change in to 18 - 15.

Now, this is just basic subtraction.

18 - 15 = 3

Therefore, 18 + (-15) = 3

6 0
4 years ago
Please help me <br><br>is test​
Luden [163]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Define an equivalence relation P on Z as follows: Let x,y e Z ; xPy if and only if ke Z s.t. x - y = 2k Show how the reflexive p
defon

Answer with Step-by-step explanation:

We are given that an equivalence relation P on Z as

Let x,y\in Z

xPy if and only if k\in Z such that x-y=2k.

We have to show that how the reflexive property and symmetric property of an equivalence relations hold for P on Z.

We know that reflexive property

a is related to a by given relations.

If xPax then we get

x-x=0=2(0)

Where k=0 and 0 belongs to integers.

Hence, the relation satisfied reflexive property.

Symmetric property :If a is related to b then b is related to b.

If x and y is related by the relation

x-y=2k where k is any integer

y-x=-2k=2(-k)

k belongs to integers.

Hence, relation satisfied  symmetric property.

7 0
3 years ago
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