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3 years ago

10

⚠️HELP in boolean please⚠️

2 answers:

Zielflug [23.3K]3 years ago

6 0

Answer:

They are technically the same

Step-by-step explanation:

Hope it helps

Readme [11.4K]3 years ago

3 0

Answer:

how did you get those warning signs in your question

Step-by-step explanation:

You might be interested in

1.)12.5+(-31.5)=<br>2.)-31.91+(-16.7)=<br>3.)1/6+(-11/12)+2/3=<br>4.)29+(-15.7)+(-31.05)=

Xelga [282]

1. = Step 1. Simplify Brackets and you get $12.5 - 31.5$ Step 2. Simplify and you get $-19
$ which is your answer.

2. = Step 1. Simplify Brackets and you get $-31.91-16.7$ Step 2. Simplify and you get $-48.61$

3. = Step 1. Simplify Brackets and you get $\frac{1}{6} - \frac{11}{12} + \frac{2}{3}$ Step 2. Simplify and you get $- \frac{1}{12}$

4. Step 1. = Simplify Brackets and you get $29-15.7-31.05$ Step 2. Simplify and you get $-17.75$

5 0

4 years ago

The number represented by x is less than 7 and is evenly divisible by both 0.6 and 2.4

svetoff [14.1K]

2.4<7
2.4 / 0.6 = 4
2.4 / 2.4 = 1

4.8<7
4.8 / 0.6 = 8
4.8 / 2.4 = 2

6 0

3 years ago

Can someone help me with this?

tino4ka555 [31]

Answer:

just add both sides 2.8+2.8=5.6

Step-by-step explanation: possible is 5.6 just put 2.8 on both

7 0

3 years ago

Read 2 more answers

Someone help please make sure the answer is right :)

Andreas93 [3]

Answer:

The answer is 2

Step-by-step explanation:

The equation =69x + 2 = 140

= 69x = 140 - 2

69x = 138

69 divided by 69 = 138 divided by 68

x = 2

6 0

3 years ago

Suppose the sample space for a probability experiment has 8 elements. If elements from the sample are selected without replaceme

Gwar [14]

Answer: Number of ways $=\dfrac{8!}{8!0!}\ or \ 1$

Step-by-step explanation:

When there is no replacement , we use combination to find the number of ways to choose things.

Number of ways to choose r things out of ( with out replacement) = $^nC_r=\dfrac{n!}{r!(n-r)!}$

The number of ways to choose 8 things = $^8C_8=\dfrac{8!}{8!(8-8)!}=\dfrac{1}{0!}=1 [\because 0!=1]$

Hence, Number of ways $=\dfrac{8!}{8!0!}\ or \ 1$

5 0

3 years ago