We will take that molar mass of Pb(CO3)2 represents the total mass of all particles in this compound, ie it has value 100%.
M(Pb(CO3)2) = Ar(Pb) + 2xAr(C) + 6xAr(O) = 207.2 + 2x12 + 6x16= 327.2 g/mol
M(Pb) = 207.2 g/mol
From the date above we can set the following ratio:
M(Pb(CO3)2) : M(Pb) = 100% : x
327.2 : 207.2 = 100 :x
x = 63.33% of Pb there is in <span>Pb(Co3)2</span>
Answer:
6 moles of SO₃ formed.
Explanation:
Given data:
Number of moles of SO₃ formed = ?
Number of moles of oxygen react = 3 mol
Solution:
Chemical equation;
2SO₂+ O₂ → 2SO₃
now we will compare the moles of oxygen and sulfur trioxide.
O₂ : SO₃
1 : 2
3 : 2/1×3 = 6 moles
Thus, six moles of SO₃ will formed.
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