B) The mutation is beneficial and allows those who have it to reproduce more than average.
If the mutation is beneficial, it will become common in a population since the individual(s) that have this beneficial mutation will survive longer to produce more offspring that have this mutation. These offspring will also live longer and spread this mutation through the gene pool through reproduction.
Hope this helps :)
I’m pretty Sure it’s A sorry if i’m wrong
This was Ernest Rutherford’s gold foil experiment. He used radioactive alpha particles as a part of the experiment and discovered that there was a densely packed, positively charged nucleus in atoms with electrons that were spread out in spaces between nuclei.
Answer:
D. If all of the offspring are short-tailed, the unknown individual is the homozygous dominant genotype.
Explanation:
The short tail phenotype is completely dominant over the long tail phenotype. When a short tailed salamander with unknown genotype is crossed with a homozygous recessive long tailed salamander, the cross is called testcross. Lets assume that the allele "S" gives "short tail" phenotype while the allele "s" gives "long tail" phenotype.
If the "short tailed salamander" with unknown genotype is homozygous dominant (SS), the process of the testcross will express only dominant trait (cross 1). On the other hand, if the "short tailed salamander" with unknown genotype is heterozygous dominant (Ss), segregation of alleles during gamete formation would form two types of gametes (cross 2). The 50% progeny would express the "long tail" phenotype while rest 50% will express the "short tail" phenotype.