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3 years ago

In function y=f(x), the ? Contains as the possible values of X, while the ? Contains all the possible values of y.

Mathematics

2 answers:

vekshin13 years ago

4 0

What are you even asking ?

bonufazy [111]3 years ago

3 0

Answer: domain, range

Step-by-step explanation:

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Adam has 1/2 quart of milk. If he pours the same amount if milk into 3 glasses. How many quarts of milk will each glass have?

MAXImum [283]

Answer:

3/2 or 1 1/2

Step-by-step explanation:

So 1/2 * 3 = 3/2 or 1.5 which as a fraction simplified is 1 1/2. Hope that helps!

3 0

3 years ago

Read 2 more answers

What should be subtracted from 3x^4 - 2x^3 + 2x^2 + 3x - 2x + 3, so that the resulting polynomial is exactly

lbvjy [14]

Answer:

185/27

Step-by-step explanation:

To get the polynomial that is exactly divisible by g(x)=3x+2, we have to divide f(x)=3x

−2x

+3x

−2x+3 by g(x) and get the remainder as shown in the above image.

Hence,

185

should be subtracted from 3x

−2x

+3x

−2x+3 so that the resulting polynomial is exactly divisible by 3x+2.

8 0

2 years ago

What are the equivalent fractions for 2 1/5 and 1 5/6 using 30 as the common denominator

Anuta_ua [19.1K]

Answer:

2 6/30 and 1 25/30

Step-by-step explanation:

First, you need to find 30÷5 and 30÷6. You do this because you need to know the multiplier when you create an equivalent fraction. 30÷5 is 6 and 30÷6 is 5. 2 1/5. You need to multiply the 1 and 5 by 6, that is 2 6/30. 1 5/6. 5 and 6 multiplied by 5 is 25 and 30. 1 5/6=1 25/30

4 0

3 years ago

Help its due in 5 mins lol

inessss [21]

Y= 26 & x=35 hope I did it on time!

6 0

3 years ago

Solve for x and y. 4x-3y=16 -2x+4y=-2 DUE 2/7/17!

Trava [24]

$\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.$

Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
 $\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.$
$\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.$
--------------------
$5y = 12$
$\boxed{\boxed{y = \frac{12}{5}}}\end{array}}\qquad\quad\checkmark$

Let's replace the value found in the first equation:
$4x-3y=16\:(I)$
$4x-3*( \frac{12}{5}) =16$
$4x - \frac{36}{5} = 16$
least common multiple (5)
$\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}$
$20x - 36 = 80$
$20x = 80 + 36$
$20x = 116$
$x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark$

4 0

3 years ago