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kondor19780726 [428]
3 years ago
15

Find the zeros of the function and state their multiplicities. y=x^4-8x^2+16

Mathematics
1 answer:
Volgvan3 years ago
7 0
   
y=0\\\\ 
x^4-8x^2+16 = 0\\\\
(x^2)^2 - 2\cdot 4 \cdot x^2 + 4^2 = 0\\\\
(x^2 - 4)^2 = 0\\\\
(x^2 - 4)(x^2 - 4)=0\\\\
(x-2)(x+2) (x-2)(x+2) = 0\\\\
(x-2)(x-2) (x+2)(x+2) = 0\\\\
\Longrightarrow~~~ x_1 = 2;~x_2 = 2;~ x_3= -2;~x_4 = -2\\\\
\text{Conclusion:}\\\\
x_1 = x_2 = 2~~~   \text{double root}\\\\
x_3 = x_4 = -2~~~   \text{double root}\\\\




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